Let your current cR, cG and cB value be 0%, and let the R, G, and B values be 100%, then you just have to iterate i = 1 to 100 with each iteration adding cRGB + i * (RGB - cRGB). You don't have to use 100 intermediate colors, you can use N of them.
function(currentColor, desiredColor, N) {
var colors = [],
cR = currentColor.R,
cG = currentColor.G,
cB = currentColor.B,
dR = desiredColor.R - cR,
dG = desiredColor.G - cG,
dB = desiredColor.B - cB;
for(var i = 1; i <= N; i++) {
colors.push(new Color(cR + i * dR / N, cG + i * dG / N, cB + i * dB / N));
}
return colors;
}
However, that won't give you very good intermediate colors. The first thing you should do is convert your colors into HSV or similar colorspace where intensity is separate from hue and saturation. That will give you much better intermediate colors. http://en.wikipedia.org/wiki/HSL_and_HSV
To do that, first convert your colors to HSV, and run the same algorithm as above, but with H S and V instead of RGB, but keep in mind that S and V have a min of 0 and max of 1, while H is represented in degrees between 0 and 360. You might have to do something with H if you want it to go from the current color to destination color as quickly as possible e.g. if cH = 10 and dH = 50, then going from 10 -> 50 is shortest, but if cH = 10 and dH = 350, then going from 10 -> -10 (same as 350 degrees) is shorter.