php check if domain equals value, then perform action

Question

I need to take a variable that contains a URL, and check to see if the domain equals a certain domain, if it does, echo one variable, if not, echo another.

$domain = "http://www.google.com/docs";
if ($domain == google.com)
{ echo "yes"; }
else
{ echo "no"; }

Im not sure how to write the second line where it checks the domain to see if $domain contains the url in the if statement.

score 15 · Accepted Answer · answered Jul 13 '09 at 21:48

15

This is done by using parse_url:

$host = parse_url($domain, PHP_URL_HOST);
if($host == 'www.google.com') {
    // do something
}

answered Jul 13 '09 at 21:48

Paolo Bergantino

480,997
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You probably want more robust domain checking, as noted in Jonathan Sampson's answer. – Drew Stephens Jul 13 '09 at 23:11
6

How is a homemade regex more robust than a PHP built in? – Paolo Bergantino Jul 14 '09 at 03:46

score 7 · Answer 2 · answered Jul 13 '09 at 21:48

Slightly more advanced domain-finding function.

$address = "http://www.google.com/apis/jquery";

if (get_domain($address) == "google.com") {
  print "Yes.";
}

function get_domain($url)
{
    $pieces = parse_url($url);
    $domain = isset($pieces['host']) ? $pieces['host'] : '';
    if (preg_match('/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[a-z\.]{2,6})$/i', $domain, $regs)) {
        return $regs['domain'];
    }
    return false;
}

score 2 · Answer 3 · answered Jul 13 '09 at 21:51

2

In addition to the other answers you could use a regex, like this one which looks for google.com in the domain name

$domain = "http://www.google.com/docs";
if (preg_match('{^http://[\w\.]*google.com/}i', $domain))
{

}

answered Jul 13 '09 at 21:51

Paul Dixon

295,876
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Yeah I didn't see what you were trying there. – Paolo Bergantino Jul 13 '09 at 21:55

score 1 · Answer 4 · answered Jul 13 '09 at 21:48

1

Have you tried parse_url()?

Note that you might also want to explode() the resulting domain on '.', depending on exactly what you mean by 'domain'.

answered Jul 13 '09 at 21:48

Bobby Jack

15,689
15
65
97

score 1 · Answer 5 · answered Jul 13 '09 at 21:48

You can use the parse_url function to divide the URL into the separate parts (protocol/host/path/query string/etc). If you also want to allow www.google.com to be a synonym for google.com, you'll need to add an extra substring check (with substr) that makes sure that the latter part of the host matches the domain you're looking for.

php check if domain equals value, then perform action

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