Exclude list items that contain values from another list

Question

There are two lists:

List<string> excluded = new List<string>() { ".pdf", ".jpg" };
List<string> dataset = new List<string>() {"valid string", "invalid string.pdf", "invalid string2.jpg","valid string 2.xml" };

How can I filter-out values from the "dataset" list which contain any keyword from the "excluded" list?

Answer 1

var results = dataset.Where(i => !excluded.Any(e => i.Contains(e)));

Answer 2

// Contains four values.
int[] values1 = { 1, 2, 3, 4 };

// Contains three values (1 and 2 also found in values1).
int[] values2 = { 1, 2, 5 };

// Remove all values2 from values1.
var result = values1.Except(values2);

https://www.dotnetperls.com/except

Answer 3

Try:

var result = from s in dataset
             from e in excluded 
             where !s.Contains(e)
             select e;

Answer 4

var result=dataset.Where(x=>!excluded.Exists(y=>x.Contains(y)));

This also works when excluded list is empty.

Answer 5

var result = dataset.Where(x => !excluded.Contains(x));