gdb disassemble by line number

Question

Say I want to disassemble lines m-n of file x, where file x is not in the current context. Is this operation possible, and if so, how? Note: I am working on x86 Linux.

I'm sure it depends on the optimization flags, and you'll only really be able to do this at `-O0`. — Dietrich Epp, Jul 01 '12 at 22:03

undercat · Answer 1 · 2019-01-13T11:50:17.997

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You can use the disassemble command with the /m key to display original C lines in front of their assembly counterparts:

disassemble /m 'my_file.c'::my_function

This does not require any preliminary steps, although it doesn't seem to accept source line ranges as you asked.

edited Jan 13 '19 at 11:50

answered Sep 09 '14 at 12:21

undercat

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score 3 · Answer 2 · answered Apr 10 '19 at 16:36

As a quite late and maybe redundant answer, but hopefully useful for someone like me, I would like to put together a complete response to this and your other question on getting the address of a line number.

The disassemble command can disassemble address ranges: disassemble [Start],[End]. But you want to disassemble line ranges.

To get the addresses of the source code lines you can use the info line command: info line [File]:[Line].

score 1 · Accepted Answer · answered Jul 01 '12 at 23:09

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Here's a kludgy way to do it: set a breakpoint on the line you're interested in, and the breakpoint acknowledgement gives you an address. Then clear the breakpoint and run disas or x/20i on that address.

answered Jul 01 '12 at 23:09

Alan Curry

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gdb disassemble by line number

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