Java - Swapping Page

Question

I have built a custom hashmap using two arrays. One contains keys another values. Now, I see sometimes JVM can't able to allocate required memory for those arrays and throws exception. Is there any method to solve this using page swapping or any other method ?

Code:

public class Test1{
public static void main(String args[]){


    try {

   int arrays[]  = new int[50000000] ;
for ( int i = 0; i < 50000000 ; i++)
        {
        arrays[i] = i ;
        }

    }

catch(Exception e){
        System.out.println(e) ;
    }
}
}

Edit:

    public void load() {
        try {
            FileChannel channel2 = new RandomAccessFile(str1, "r").getChannel();
            MappedByteBuffer mbb2 = channel2.map(FileChannel.MapMode.READ_ONLY, 0, channel2.size());
            mbb2.order(ByteOrder.nativeOrder());
            assert mbb2.remaining() == savenum * 8;
            for (int i = 0; i < savenum; i++) {
                long l = mbb2.getLong();
                keys[i] = l;
            }
            channel2.close();

            FileChannel channel3 = new RandomAccessFile(str2, "r").getChannel();
            MappedByteBuffer mbb3 = channel3.map(FileChannel.MapMode.READ_ONLY, 0, channel3.size());
            mbb3.order(ByteOrder.nativeOrder());
            assert mbb3.remaining() == savenum * 4;
            for (int i = 0; i < savenum; i++) {
                int l1 = mbb3.getInt();
                values[i] = l1;
            }
            channel3.close();
        } catch (Exception e) {
            System.out.println(e);
        }
    }

    public void save() {
        try {
            FileChannel channel = new RandomAccessFile(str1, "rw").getChannel();
            MappedByteBuffer mbb = channel.map(FileChannel.MapMode.READ_WRITE, 0, savenum * 8);
            mbb.order(ByteOrder.nativeOrder());

            for (int i = 0; i < savenum; i++) {
                mbb.putLong(keys[i]);
            }
            channel.close();

            FileChannel channel1 = new RandomAccessFile(str2, "rw").getChannel();
            MappedByteBuffer mbb1 = channel1.map(FileChannel.MapMode.READ_WRITE, 0, savenum * 4);
            mbb1.order(ByteOrder.nativeOrder());

            for (int i = 0; i < savenum; i++) {
                mbb1.putInt(values[i]);
            }
            channel1.close();
        } catch (Exception e) {
            System.out.println("IOException : " + e);
        }
    }

Answer 1

Modifying your code to use an IntBuffer and LongBuffer

class LongIntParallelHashMultimap {
    private static final int NULL = 0;
    private final FileChannel channel1, channel2;
    private final LongBuffer keys;
    private final IntBuffer values;
    private final int capacity;
    private int size;

    public LongIntParallelHashMultimap(int capacity, String basename) throws IOException {
        assert (capacity & (capacity - 1)) == 0 : "Capacity " + capacity + " must be a power of 2";
        this.capacity = capacity;
        channel1 = new RandomAccessFile(basename + ".keys", "rw").getChannel();
        keys = channel1.map(FileChannel.MapMode.READ_WRITE, 0, capacity * 8).order(ByteOrder.nativeOrder()).asLongBuffer();
        // load keys into memory
        for(int i=0;i<capacity;i+=512) keys.get(i);

        channel2 = new RandomAccessFile(basename + ".values", "rw").getChannel();
        values = channel2.map(FileChannel.MapMode.READ_WRITE, 0, capacity * 4).order(ByteOrder.nativeOrder()).asIntBuffer();
        for(int i=0;i<capacity;i+=1024) values.get(i);
    }

    public void put(long key, int value) {
        long key1 = key + 1;
        int index = indexFor(key1);
        while (keys.get(index) != NULL) {
            index = successor(index);
        }
        values.put(index, value);
        keys.put(index, key1);
        ++size;
    }

    /**
     * Uses a pre-allocated array and return the count of matches.
     */
    public int get(long key, int[] hits) {
        long key1 = key + 1;
        int index = indexFor(key1);
        int hitIndex = 0;

        while (keys.get(index) != NULL) {
            if (keys.get(index) == key1) {
                hits[hitIndex] = values.get(index);
                ++hitIndex;
            }
            index = successor(index);
        }

        return hitIndex;
    }

    private int indexFor(long key) {
        return Math.abs((int) ((key * 5700357409661598721L) & (capacity - 1)));
    }

    private int successor(int index) {
        return (index + 1) & (capacity - 1);
    }

    public int size() {
        return size;
    }

    public void close() {
        try {
            channel1.close();
            channel2.close();
        } catch (IOException ignored) {
        }
        try {
            ((DirectBuffer) keys).cleaner().clean();
            ((DirectBuffer) values).cleaner().clean();
        } catch (Throwable notSupportedOnThisPlatform) {
        }
    }
}

---

To allow the OS to swap the pages of your data structure you need to use off heap memory or memory mapped files. The memory mapped files are easier to manage and can be up to the size of your hard drive in size.

long heap = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory();
RandomAccessFile raf = new RandomAccessFile("array.dat", "rw");
IntBuffer map = raf.getChannel().map(FileChannel.MapMode.READ_WRITE, 0, 1 << 30).order(ByteOrder.nativeOrder()).asIntBuffer();
for (int i = 0; i < map.capacity(); i++)
    map.put(i, i);
long heap2 = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory();
System.out.printf("Wrote %,d int values, heap used %,d bytes approx%n", map.capacity(), heap2 - heap);

prints

Wrote 268,435,456 int values, heap used 0 approx

BTW: You need a 64-bit JVM to map this data all at once. If you have a 32-bit JVM you will need to move the mapping around (which is a pain so use a 64-bit JVM if you can)

If you have a 200 MB array, this should fit into a 32-bit JVM.