I have a lists:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456', 'def-111', 'qwe-111']
bad = ['abc', 'def']
and want to search for items that contain the string 'abc' and 'def' (and others in bad). How can I do that?
Almost same question here.
If you just want a test, join the target list into a string and test each element of bad like so:
>>> my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456', 'def-111', 'qwe-111']
>>> bad = ['abc', 'def']
>>> [e for e in bad if e in '\n'.join(my_list)]
['abc', 'def']
From your question, you can test each element as a sub string against the each element of the other this way:
>>> [i for e in bad for i in my_list if e in i]
['abc-123', 'abc-456', 'def-456', 'def-111']
It is fast (in comparison to one of the other methods):
>>> def f1():
... [item for item in my_list if any(x in item for x in bad)]
...
>>> def f2():
... [i for e in bad for i in my_list if e in i]
...
>>> timeit.Timer(f1).timeit()
5.062238931655884
>>> timeit.Timer(f2).timeit()
1.35371994972229
From your comment, here is how you get the elements that do not match:
>>> set(my_list)-{i for e in bad for i in my_list if e in i}
{'ghi-789', 'qwe-111'}
In [4]: filter(lambda item: any(x in item for x in bad), my_list)
Out[4]: ['abc-123', 'def-456', 'abc-456', 'def-111']
or
In [13]: [item for item in my_list if any(x in item for x in bad)]
Out[13]: ['abc-123', 'def-456', 'abc-456', 'def-111']
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
bad = ['abc', 'def']
for s in some_list:
for item in bad:
if item in s:
print 'Found ', s
It's simple, works fine and fast( only if your list is not very big.)
some_list=['abc-123', 'def-456', 'ghi-789', 'abc-456']
bad = ['abc', 'def']
for i in range (0,len(bad)):
if bad[i] in some_list:
print('Found a bad entry:', bad[i])
