Unknown modifier 'v' when using preg_match() expression in regex

Question

        $regex = '/\b'.$keyword.'\b/i'; // case insensitive match
        if (preg_match($regex, $linkedin_html) == 0)
        {
            $this->_htmlValidationFailed++;
            continue;                
        }

When I use this code.. i get error as unknown modifier 'v'..

pls let me know what is the problem and help me rectify.

What is `$keyword`? Probably it have a `/v` and you need `escape` it. — David Rodrigues, Jul 09 '12 at 11:41
Impossible to answer unless you show us what the value of `$keyword` is. I suspect, like David, it contains something the REGEX engine is attempting to parse as REGEX grammar. — Mitya, Jul 09 '12 at 11:44
we cant know what $keyword is beforehand.. it is some required information fetched from internet while running the code.. and each time it varies for different input. — Naren Karthik, Jul 09 '12 at 11:46

score 3 · Answer 1 · answered Jul 09 '12 at 11:44

3

<?php
$keyword = preg_quote( $keyword, '/' );

$regex = '/\b'.$keyword.'\b/i'; // case insensitive match
if (preg_match($regex, $linkedin_html) == 0)
{
   $this->_htmlValidationFailed++;
   continue;                
}

answered Jul 09 '12 at 11:44

Berry Langerak

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thanks berry.. but now it says..Warning: preg_match(): Compilation failed: regular expression is too large at offset #######. – Naren Karthik Jul 09 '12 at 11:55
@NarenKarthik Well, I'm guessing that means that your regular expression is too large ;) If you're just testing for keywords, maybe a loop with strstr is a better fit than a regular expression? – Berry Langerak Jul 09 '12 at 13:06

Unknown modifier 'v' when using preg_match() expression in regex

1 Answers1

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