httpclient post xml content in java

Question

I am trying to use httpclient to post xml request as following:

String parm1 = MyXml.toString();
PostMethod post = new Postmethod(url);
post.setRequestEntity(new StringRequestEntity(parm1));
...

I have an object in the program which I want to convert it to xml representation.

My question is that what is the best way to create Myxml in xml format in java which then I can simply print out its String format later.

Thanks.

Are you asking for the best way to create a `toXML()` method or are you asking something about the technique for POSTing data? — Larry OBrien, Jul 09 '12 at 19:08
I am more interested in creating a xml that later I can use it to pass in parameter for the http post. So, I guess I am kinda asking both. — Tony, Jul 09 '12 at 19:17
you could look at http://www.mkyong.com/tutorials/java-xml-tutorials/ for the XML part. — OVB, Jul 09 '12 at 19:21

score 0 · Answer 1 · edited May 23 '17 at 12:27

0

There are many options for creating XML in Java. This answer How to serialize and de-serialize objects using JAXB? provides a good demo of one common way that seems to fit your use-case.

edited May 23 '17 at 12:27

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answered Jul 09 '12 at 19:51

Larry OBrien

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score 0 · Answer 2 · answered Oct 11 '12 at 20:16

Here is how you can post xml request using Apache HttpClient.

Use apache Velocity to create the request xml format

Use Castor to convert response stream( respReader ) into java object

final String request = createXmlRequest(); // helper method to create the xml request
final HttpClient client = new HttpClient();
final PostMethod post = new PostMehod(url); // url - www.google.cm/someoperaion

post.setRequestHeader("Content-Language", "en-US");
post.setRequestEntity(new StringRequestEntity(request, "text/xml", "ISO-8859-1"));

final int returnCode = client.executeMethod(post);

final BufferedReader respReader = new BufferedReader(new InputStreamReader(post.getResponseBodyAsStream()));

score -1 · Answer 3 · answered Jul 09 '12 at 19:06

Try to use it this way...

public void postData() throws Exception {


 HttpClient client = new DefaultHttpClient();
 HttpPost httppost = new HttpPost("https://www.xyz.com");

 List<NameValuePair> list = new ArrayList<NameValuePair>(1);

 list.add(new BasicNameValuePair("name","ABC");

 httppost.setEntity(new UrlEncodedFormEntity(list));

 HttpResponse r = client.execute(httppost);

}

httpclient post xml content in java

3 Answers3