How to parse JSON string in php

Question

I'm getting below JSON response:

[{"startDate":"2012-07-12 11:21:38 +0530","totalTime":0},{"startDate":"2012-07-11 11:27:33 +0530","totalTime":0},{"startDate":"2012-07-16 18:38:37 +0530","totalTime":0},{"startDate":"2012-07-17 14:18:32 +0530","totalTime":0}]

i want make array of start date and totalTime, i have used these two lines but it wont work $obj, please suggest..

                    $obj  = json_decode($dateTimeArr); 
        $dateAr = $obj->{'startDate'};

score 2 · Answer 1 · answered Jul 17 '12 at 10:00

2

It is very easy:

$Arr = json_decode($JSON, true);

answered Jul 17 '12 at 10:00

Roman Newaza

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Zagor23 · Accepted Answer · 2012-07-17T12:27:03.320

2

As everyone said, and you did - use json_decode.

    $dateArrays  = json_decode($dateTimeArr, true); // decode JSON to associative array
    foreach($dateArrays as $dateArr){
        echo $dateArr['startDate']; 
        echo $dateArr['totalTime']; 
    }

In future, if you are unsure what type or structure of data is in the variable, do var_dump($var) and it will print type of variable and its content.

edited Jul 17 '12 at 12:27

answered Jul 17 '12 at 12:08

Zagor23

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score 1 · Answer 3 · answered Jul 17 '12 at 09:59

1

json_decode() will give you nested PHP types you can then descend to retrieve your data.

answered Jul 17 '12 at 09:59

Ignacio Vazquez-Abrams

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i want make array of start date, i have used these two lines but it wont work $obj, please suggest.. $obj = json_decode($dateTimeArr); $dateAr = $obj->{'startDate'}; – Vee Mandke Jul 17 '12 at 10:05

score 1 · Answer 4 · answered Jul 17 '12 at 10:04

1

use json_decode($json_response,true) to convert json to Array

answered Jul 17 '12 at 10:04

Krishna

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score 0 · Answer 5 · edited Jul 17 '12 at 10:05

0

Guess what you are looking for is json_decode()

Check out http://php.net/manual/en/function.json-decode.php for the inner workings

edited Jul 17 '12 at 10:05

Dale

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answered Jul 17 '12 at 10:00

Gerald Versluis

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i want make array of start date, i have used these two lines but it wont work $obj, please suggest.. $obj = json_decode($dateTimeArr); $dateAr = $obj->{'startDate'}; – Vee Mandke Jul 17 '12 at 10:04
1

@rekire It isn't actually in this case but I agree that's ugly http://stackoverflow.com/questions/5643496/are-php-functions-case-sensitive – allen213 Jul 17 '12 at 10:07
2

Try this: `$obj = json_decode($dateTimeArr); $dateAr = $obj->startDate;` You're mixing up object and array notation there – Dale Jul 17 '12 at 10:07

How to parse JSON string in php

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