Find only file name from full path of the file in vc++

Question

Suppose there is a CString variable which store the full path of the file.Now I hava to find only file name from if.How to do it in vc++.

CString FileName = "c:\Users\Acer\Desktop\FolderName\abc.dll";

Now I want only abc.dll.

I recommend the function decomposePath described [here](http://stackoverflow.com/questions/8520560/get-a-file-name-from-a-path/42424844#42424844). — no one special, Feb 23 '17 at 19:51

Some programmer dude · Answer 1 · 2012-07-17T11:31:50.020

15

You can use PathFindFileName.

Remember that you have to escape the \ character in your path string!

edited Jul 17 '12 at 11:31

answered Jul 17 '12 at 11:26

Some programmer dude

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@Mark, Why to convert? If it is char* - ANSI build, pass char* ! – Ajay Jul 18 '12 at 08:08

score 13 · Accepted Answer · answered Jul 17 '12 at 11:43

13

Same as already stated above, but as u are using MFC framework, this would be the way to do it. Though this does not check files existence.

CString path= "c:\\Users\\Acer\\Desktop\\FolderName\\abc.dll";
CString fileName= path.Mid(path.ReverseFind('\\')+1);

answered Jul 17 '12 at 11:43

Aleksandar

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BTW CString is not just for MFC - see . More at http://msdn.microsoft.com/en-us/library/ms174288.aspx – JBRWilkinson Jul 17 '12 at 13:21

score 7 · Answer 3 · answered Jul 17 '12 at 11:31

7

std::string str = "c:\\Users\\Acer\\Desktop\\FolderName\\abc.dll";
std::string res = str.substr( str.find_last_of("\\") + 1 );

Will get you "abs.dll".

answered Jul 17 '12 at 11:31

SingerOfTheFall

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Why use std::string when you have CString which has the required functions – mmmmmm Jul 17 '12 at 11:51

score 2 · Answer 4 · answered Jul 17 '12 at 11:32

I would use Boost::FileSystem for filename manipulation as it understands what the parts of a name would be. The function you want here would be filename()

If you are just getting the filename you can do this using CString functions. First find the ast backslash using ReverseFind and then Right to get the string wanted.

score 0 · Answer 5 · answered Jul 17 '12 at 11:37

The code below demonstrate extracting a file name from a full path

#include <iostream>
#include <cstdlib>
#include <string>
#include <algorithm>

std::string get_file_name_from_full_path(const std::string& file_path)
{
    std::string file_name;

    std::string::const_reverse_iterator it = std::find(file_path.rbegin(), file_path.rend(), '\\');
    if (it != file_path.rend())
    {
        file_name.assign(file_path.rbegin(), it);
        std::reverse(file_name.begin(), file_name.end());
        return file_name;
    }
    else
        return file_name;
}

int main()
{
    std::string file_path = "c:\\Users\\Acer\\Desktop\\FolderName\\abc.dll";
    std::cout << get_file_name_from_full_path(file_path) << std::endl;
    return EXIT_SUCCESS;
}

Find only file name from full path of the file in vc++

5 Answers5