I am trying to replace a character at a specific position of a string.
For example:
String str = "hi";
replace string position #2 (i) to another letter "k"
How would I do this? Thanks!
Petar Ivanov's answer to replace a character at a specific index in a string question
String are immutable in Java. You can't change them.
You need to create a new string with the character replaced.
String myName = "domanokz";
String newName = myName.substring(0,4)+'x'+myName.substring(5);
Or you can use a StringBuilder:
StringBuilder myName = new StringBuilder("domanokz");
myName.setCharAt(4, 'x');
System.out.println(myName);
Kay!
First of all, when dealing with strings you have to refer to their positions in 0 base convention. This means that if you have a string like this:
String str = "hi";
//str length is equal 2 but the character
//'h' is in the position 0 and character 'i' is in the postion 1
With that in mind, the best way to tackle this problem is creating a method to replace a character at a given position in a string like this:
Method:
public String changeCharInPosition(int position, char ch, String str){
char[] charArray = str.toCharArray();
charArray[position] = ch;
return new String(charArray);
}
Then you should call the method 'changeCharInPosition' in this way:
String str = "hi";
str = changeCharInPosition(1, 'k', str);
System.out.print(str); //this will return "hk"
If you have any questions, don't hesitate, post something!
Use StringBuilder
:
StringBuilder sb = new StringBuilder(str);
sb.setCharAt(i - 1, 'k');
str = sb.toString();
To replace a character at a specified position :
public static String replaceCharAt(String s, int pos, char c) {
return s.substring(0,pos) + c + s.substring(pos+1);
}
If you need to re-use a string, then use StringBuffer:
String str = "hi";
StringBuffer sb = new StringBuffer(str);
while (...) {
sb.setCharAt(1, 'k');
}
EDIT:
Note that StringBuffer is thread-safe, while using StringBuilder is faster, but not thread-safe.