my problem with vsprintf
is that I can not obtain input arguments directly, I have to first get inputs one by one and save them in void**
, then pass this void**
to vsprintf()
, it is all fine for windows, but when I come to 64bit linux, gcc cannot compile because it is not allowed to convert from void**
to va_list
, Is there anyone can give me some help how I should do under linux?
part of my code is:
void getInputArgs(char* str, char* format, ...)
{
va_list args;
va_start(args, format);
vsprintf(str, format, args);
va_end(args);
}
void process(void)
{
char s[256];
double tempValue;
char * tempString = NULL;
void ** args_ptr =NULL;
ArgFormatType format; //defined in the lib I used in the code
int numOfArgs = GetNumInputArgs(); // library func used in my code
if(numOfArgs>1)
{
args_ptr = (void**) malloc(sizeof(char)*(numOfArgs-1));
for(i=2; i<numOfArgs; i++)
{
format = GetArgType(); //library funcs
switch(format)
{
case ArgType_double:
CopyInDoubleArg(i, TRUE, &tempValue); //lib func
args_ptr[i-2] = (void*) (int)tempValue;
break;
case ArgType_char:
args_ptr[i-2]=NULL;
AllocInCharArg(i, TRUE, &tempString); //lib func
args_ptr[i-2]= tempString;
break;
}
}
}
getInputArgs(s, formatString, (va_list) args_ptr); /////Here is the location where gcc cannot compile
}
Many Many thanks!!