In Java, I want to take a string representing a hex and convert it to an int while preserving the "0x" prefix

Question

See how int a and int b have the prefix "0x" before the hex value? I want to make more of these from a string. I tried to use parseInt from Integer, but I get a NumberFormatException. Can anyone help?

int a = 0xA;
int b = 0x4;
String f = "0xF";    
int d = Integer.parseInt(f, 16);

I want "int d = 0xF"

Does it really matter that much? As far as I know, you'd have to manually strip it off anyway, it probably isn't worth it. — Wug, Jul 31 '12 at 18:04

score 6 · Accepted Answer · answered Jul 31 '12 at 18:06

6

How about this?

String f = "0xF";    
int d = Integer.parseInt(f.substring(2), 16);
System.out.println(d);

OUTPUT:

answered Jul 31 '12 at 18:06

Eng.Fouad

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score 3 · Answer 2 · edited May 23 '17 at 12:13

3

Try:

Integer.decode("0x64");

A similar question was asked before in SO, here's a link for more info:

Parsing integer strings in Java

edited May 23 '17 at 12:13

Community

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answered Jul 31 '12 at 18:09

ali

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In Java, I want to take a string representing a hex and convert it to an int while preserving the "0x" prefix

2 Answers2