Path to a file without basename

Question

How can I get the path of a file without the file basename?

Something like /a/path/to/my/file.txt --> /a/path/to/my/

Tried to use .split('/') but it's not clean, since you have to add the final /, and it's not compatible with all OSes.

Answer 1

Use os.path.dirname(filename).

Answer 2

You can import os

>>> filepath
'/a/path/to/my/file.txt'
>>> os.path.dirname(filepath)
'/a/path/to/my'
>>> 

Answer 3

(dirname, filename) = os.path.split(path)

Answer 4

Since Python 3.4 you can use Pathlib.

from pathlib import Path

path = Path("/a/path/to/my/file.txt")
print(path.parent)

Answer 5

Check subs of os.path

os.path.dirname('/test/one')