C++ why I retrieve double as this format

Question

Possible Duplicate:
double truncates at 7 characters of output

1.4547e+08

If i see the data itself, it should be

1.45470197.00

anyone got any idea how to convert that double 1.4547e+08 back to this 1.45470197.00

The format you given 1.45470197.00 isn't valid, there are no numbers with more than one decimal point. Do you mean 145,470,197.00? — Mithrandir, Aug 04 '12 at 19:38
FYI, that “format” is called [scientific notation](http://en.wikipedia.org/wiki/Scientific_notation). — , Aug 04 '12 at 19:39
Please consider *accepting* answers to previous questions. Do you really mean `1.45470197.00`, with *two* decimal points? — thb, Aug 04 '12 at 19:40

score 5 · Answer 1 · answered Aug 04 '12 at 19:39

5

If you're printing data with std::cout, use std::fixed to prevent scientific notation

double d = 145470197.00;
std::cout << std::fixed << d;

answered Aug 04 '12 at 19:39

Kent

How do i use fixed for assigning the value to variable – Baoky A New Programer Aug 04 '12 at 19:45
1

@BaokyANewProgramer: You can't, unless you want to store it as a string, in which case, you lose your ability to do math on it. The double is not stored as 145470197.00, or as 1.4547e+08, it is stored as a series of bits in (most likely) [this format](http://en.wikipedia.org/wiki/IEEE_floating_point). The decimal number you see on screen is only how the ostream function chooses to interpret those bits. – Benjamin Lindley Aug 04 '12 at 19:55

1 Answers1