Add resource file to artifact in Intellij Idea

Question

I'm creating a plugin to de reflected and call by main application. This plugin uses xml file and I want to make it embedded resource. I build plugin as artifact (JAR). My actions:

1) Put xml file to directory 'trunk/res' configured as 'source root';

2) Performed 'make module' action for the module in which directory 'trunk/res' is;

3) Into the plugin I access xml file through file path dom = db.parse("trunk//res//resource.xml");

But when I call plugin from the main application I get this exception about system cannot find the file 'MainApp/trunk/trunk/res/resource.xml'. I guess I don't extract resource properly, but how to do it correctly?

If `trunk/res` is a root, why do you specify it in the path? How does `db.parse` load the resource? Why double slashes? — CrazyCoder, Aug 06 '12 at 10:07
Yes, Artifacts|Output Layout shows that jar contains `resource.xml (...\PlugnProject\trunk\res)` — Zharro, Aug 06 '12 at 10:11
@Zharro can you unzip your jar and check if `resource.xml` is really inside it and show structure of the jar file. — Mikita Belahlazau, Aug 06 '12 at 10:18
@Nikita Beloglazov It is. Jar contains file: `JarContent\res\resource.xml` — Zharro, Aug 06 '12 at 10:27
`dom = db.parse("trunk//res//resource.xml")` where does this code called? From the main application or from plugin? — Mikita Belahlazau, Aug 06 '12 at 10:29
@Zharro yes, you need to load file using `getResourceAsStream` method. Check this: http://stackoverflow.com/questions/4585553/how-to-load-resource-from-jar-file-packaged-in-a-war-file — Mikita Belahlazau, Aug 06 '12 at 10:40
@NikitaBeloglazov thanx, but what to pass to getResourceAsStream()? I tried `InputStream xmlFileStream = classLoader.getResourceAsStream("res\\AIP_82.xml")`, but xmlFileStream == null. — Zharro, Aug 06 '12 at 11:00

score 1 · Accepted Answer · answered Aug 06 '12 at 11:36

1

Try to call:

System.out.println(getClass().getProtectionDomain().getCodeSource().getLocation());

And see if you're really calling from jar. And then

InputStream xmlFileStream = getClass().getClassloader().getResourceAsStream("res\\AIP_82.xml")

answered Aug 06 '12 at 11:36

Mikita Belahlazau

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Add resource file to artifact in Intellij Idea

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