Bad index in object

Question

I have object with bad indexes. I can't edit this, because i application this working ok.

var object = { "aaa": 1, "aaa": 2, "aaa" : 3, "aaa" : 4};
$.each(object, function(key, value){

});

how can i remove all values where value = 2 and 4?

if you add the same key, it will overwrite the previous value. — Shreedhar, Aug 07 '12 at 13:29
@TomMesgert The issue is your example. The object uses the same key 4 times, which is either a syntax error or an overriding key. Is this the actual object from your code? If not and that's just your attempt to generalize it, please adjust it to resolve the confusion it's causing -- `{ "aaa": 1, "bbb": 2, ... }`. — Jonathan Lonowski, Aug 07 '12 at 13:33
possible duplicate of [How to remove a property from a javascript object](http://stackoverflow.com/questions/208105/how-to-remove-a-property-from-a-javascript-object) — Felix Kling, Aug 07 '12 at 13:37

Maël Nison · Accepted Answer · 2012-08-07T13:38:29.880

4

You can't. Every value overwrites the previous one in the literal.

$> ({ "aaa": 1, "aaa": 2, "aaa" : 3, "aaa" : 4});
Object
    aaa : 4
$>

You will have to ensure that the object literal is well-formed, then use something like this (ES5) :

var filteredObject = Object.keys( yourObject ).reduce( function ( target, key ) {
    if ( yourObject[ key ] !== 2 && yourObject[ key ] !== 4 )
        target[ key ] = yourObject[ key ];
    return target;
}, { } );

edited Aug 07 '12 at 13:38

answered Aug 07 '12 at 13:31

Maël Nison

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Nison is correct, your object will always be `Object { aaa=4 }`. See this fiddle to demonstrate the result. http://jsfiddle.net/SUpwM/ `console.log(object);` will show you the object. – Nope Aug 07 '12 at 13:37
Technically this is a well-formed object literal [as per ECMAScript 3](http://interglacial.com/javascript_spec/a-11.html#a-11.1.5). – Tgr Aug 07 '12 at 13:42

score 1 · Answer 2 · answered Aug 07 '12 at 13:29

1

Can't you simply do an if(value!=2 && value!=4) into the for?

answered Aug 07 '12 at 13:29

Lord Spectre

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Create a new empty object and add the elements from the first to the second only if they match your condition. The $.filter instead is for an array of JQuery objects. – Lord Spectre Aug 07 '12 at 13:31

score 1 · Answer 3 · answered Aug 07 '12 at 13:36

You can try the delete keyword to remove the key and that will remove the value

Here is the code

var object = { "a": 1, "b": 2, "c" : 3, "d" : 4};
$.each(object, function(key, value){
   if(value==2 || value==4){
         delete object[key];
   }
});

Note : I assumed that the same keys in your example is an error.

score 1 · Answer 4 · edited Aug 07 '12 at 14:06

1

To remove all values where value == 4:

for (var member in object) { if (object[member]==4) {delete object[member]} }

edited Aug 07 '12 at 14:06

Holger Brandt

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answered Aug 07 '12 at 13:37

nuno

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score 0 · Answer 5 · answered Aug 07 '12 at 13:29

0

I think you would want to use filter instead of each.

answered Aug 07 '12 at 13:29

Daniel A. White

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Bad index in object

5 Answers5