how to send js function as parameter to another function?

Question

I have the following code

function exec(param1,p2,fun){
    xmlhttp=new XMLHttpRequest();
    xmlhttp.onreadystatechange=function(fun){
        data=xmlhttp.responseText;
        fun(data);
    }
    // rest ajax connection code
}

when i call

 exec(param1,param2,
    function(data){
      alert (data);
    });

it says

Object not a function

in the definition at line fun('test');

any ideas ?

am sorry guys , its related to ajax onreadystatechange :s i updated the sample code — Rami Dabain, Aug 07 '12 at 18:56
http://stackoverflow.com/questions/5373278/variable-shadowing-in-javascript — Matt Ball, Aug 07 '12 at 19:03

score 1 · Accepted Answer · answered Aug 07 '12 at 18:57

You are overwriting fun with a new one in a narrower scope:

function exec(param1,p2,fun){
                        ^^^  - The function you pass

xmlhttp.onreadystatechange=function(fun){
                                    ^^^ - new variable (possibly an event object)

Change one of the variable names so you aren't masking it inside your callback function.

how to send js function as parameter to another function?

1 Answers1