Get Yesterday's date in solaris

Question

I am running SunOS.

bash-3.00$ uname -a
SunOS lvsaishdc3in0001 5.10 Generic_142901-02 i86pc i386 i86pc

I need to find Yesterday's date in linux with the proper formatting passed from command prompt. When I tried like this on my shell prompt-

bash-3.00$ date --date='yesterday' '+%Y%m%d'
date: illegal option -- date=yesterday
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]

I always get date illegal option, why is it so? Is there anything wrong I am doing?

Update:-

bash-3.00$ date --version
date: illegal option -- version
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]

That is not working for me. Is there any information you need from me, like why it is not working? — AKIWEB, Aug 07 '12 at 22:37
What does `date --version` say? (post the results in your question, not in a comment because formatting will get hosed) — Jon Lin, Aug 07 '12 at 22:38
You're not using GNU `date`, so you're not going to have access to all of the fancy options people are talking about. You can *install* GNU date for Solaris, or you could write a small Perl/Python/etc script that could do the same thing. — larsks, Aug 07 '12 at 22:53
@JonLin Not all the world's a Linux box. Not all the world's a GNU date. — Jens, Dec 16 '15 at 20:48

score 10 · Accepted Answer · answered Aug 07 '12 at 22:52

10

Try this below thing. It should work

YESTERDAY=`TZ=GMT+24 date +%Y%m%d`; echo $YESTERDAY

answered Aug 07 '12 at 22:52

arsenal

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Using this solution you might have problem if you run this batch around (-1h,+1h) midnight. It depends on the TZ, so make sure to set up your current TZ, i.e., CET or GMT+1, etc. – Enrico Giurin Apr 14 '16 at 12:16

score 3 · Answer 2 · answered Aug 07 '12 at 22:55

3

Try this one out:

DATE_STAMP=`TZ=GMT+24 date +%Y%m%d`

where GMT is the time zone and you might need to alter the 24 according to the hours difference you have from GMT. Either that or you can change GMT to a time zone more comfortable to you e.g. CST

answered Aug 07 '12 at 22:55

George Karanikas

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amdn · Answer 3 · 2012-08-07T23:15:29.767

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As larsks suggested, you can use perl:

perl -e 'use POSIX qw(strftime); print strftime "%a %b %e %H:%M:%S %Y",localtime(time()- 3600*24);'

Slightly modified from

http://blog.rootshell.be/2006/05/04/solaris-yesterday-date/

To get YYYYMMDD format use this

perl -e 'use POSIX qw(strftime); print strftime "%Y%m%d",localtime(time()- 3600*24);'

This link explains how to format date and time with strftime

http://perltraining.com.au/tips/2009-02-26.html

edited Aug 07 '12 at 23:15

answered Aug 07 '12 at 22:57

amdn

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How can I get only the `YearMonthDay` from that perl script? like 20120706 – AKIWEB Aug 07 '12 at 23:06
I edited my answer above to include the YearMonthDay format you requestd. – amdn Aug 08 '12 at 05:00

olivecoder · Answer 4 · 2016-07-18T08:04:36.573

A pure bash solution

#!/bin/bash                                                                                                                                                              

# get and split date                                                                                                                                                     
today=`date +%Y%m%d`
year=${today:0:4}
month=${today:4:2}
day=${today:6:2}

# avoid octal mismatch                                                                                                                                                   
if (( ${day:0:1} == 0 )); then day=${day:1:1}; fi
if (( ${month:0:1} == 0 )); then month=${month:1:1}; fi

# calc                                                                                                                                                                   
day=$((day-1))
if ((day==0)); then
    month=$((month-1))
    if ((month==0)); then
        year=$((year-1))
        month=12
    fi
    last_day_of_month=$((((62648012>>month*2&3)+28)+(month==2 && y%4==0)))
    day=$last_day_of_month
fi

# format result                                                                                                                                                          
if ((day<10)); then day="0"$day; fi
if ((month<10)); then month="0"$month; fi
yesterday="$year$month$day"
echo $yesterday

All the date computation strikes me as reinventing the wheel. Why not use a tool that has it built-in? — Jens, Jul 26 '13 at 11:32
There are extra spaces in the `day = last_day_of_month` statement; Fix it and I'll give you a +1, especially as otherwise your solution is the only one which always gives a correct reply whatever the timezone. — jlliagre, Sep 06 '13 at 07:22
@Jens, there might be a tool that has the solution built-in but then suggest it as a reply. All of the (current) remaining replies are more or less often giving an incorrect date. Reinventing the wheel might be necessary if you want a perfectly round one but find none. The accepted answer is quite a square wheel by the way ... — jlliagre, Sep 06 '13 at 07:31

score 1 · Answer 5 · edited Dec 16 '15 at 21:06

1

TZ=$TZ+24 date +'%Y/%m/%d' in SunOS.

edited Dec 16 '15 at 21:06

zero323

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answered Dec 16 '15 at 20:44

Arun

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This the unique and perfect solution. It works no matter from the TZ as long as the TZ variable is correctly set. Thanks – Enrico Giurin Apr 14 '16 at 12:21

score 0 · Answer 6 · edited Jul 26 '13 at 11:42

Playing on Solaris10 with non-GMT environment, I'm getting this:

# date 
Fri Jul 26 13:09:38 CEST 2013 (OK)

# (TZ=CEST+24 date)
Thu Jul 25 11:09:38 CEST 2013 (ERR)

# (TZ=GMT+24 date)
Thu Jul 25 11:09:38 GMT 2013  (OK)

# (TZ=CEST+$((24-$((`date "+%H"`-`date -u "+%H"`)))) date)
Thu Jul 25 13:09:38 CEST 2013  (OK)

As You colud see, I have and I want to get CEST , but TZ=CEST+24 giving me wrong CEST data; GMT+24 giving me correct data, but unusable.

To get the proper result, I has to use GMT+22 (wrong command, correct result) or CEST+22 (wrong value, but finnaly correct result for correct TZ)

score 0 · Answer 7 · edited Jun 20 '16 at 06:02

0

A pure bash solution given by @olivecoder is very reliable compared to any other solution but there is a mistake to be corrected. when the day fall on 1st of the month the script is failing with date saying "last_day_of_month" in day value. @olivecoder has missed $ in day=last_day_of_month, that it should be

day=$last_day_of_month;

After this correction it works very good.

Using Timezone -24 is having some issue based on time when use it. in some cases it goes to day before yesterday. So I think its not reliable.

edited Jun 20 '16 at 06:02

ρяσѕρєя K

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answered Jun 20 '16 at 05:45

I fixed my solution as suggested. Thanks! – olivecoder Jul 18 '16 at 08:05

Get Yesterday's date in solaris

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