How do I call a web service from javascript

Question

Say I have a web service http://www.example.com/webservice.pl?q=google which returns text "google.com". I need to call this web service (http://www.example.com/webservice.pl) from a JavaScript module with a parameter (q=google) and then use the return value ("google.com") to do further processing.

What's the simplest way to do this? I am a total JavaScript newbie, so any help is much appreciated.

Prestaul · Answer 1 · 2018-05-07T19:30:03.590

14

EDIT:

It has been a decade since I answered this question and we now have support for cross-domain XHR in the form of CORS.

For any modern app consider using fetch to make your requests. If you need support for older browsers you can add a polyfill.

Original answer:

Keep in mind that you cannot make requests across domains. For example, if your page is on yourexample.com and the web service is on myexample.com you cannot make a request to it directly.

If you do need to make a request like this then you will need to set up a proxy on your server. You would make a request to that proxy page, and it will retrieve the data from the web service and return it to your page.

edited May 07 '18 at 19:30

answered Sep 23 '08 at 03:14

Prestaul

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i want to get data form other site without using proxy, are there solution to resolcve this problem – Ayoub Benayache Apr 16 '18 at 23:49
1

@AyoubBenayache, yes, you have to implement CORS headers (which weren't available when this answer was written a decade ago). There is a ton of good information about this if you just search CORS. – Prestaul May 07 '18 at 19:22

score 12 · Accepted Answer · answered Sep 23 '08 at 01:10

Take a look at one of the many javascript libraries out there. I'd recommend jQuery, personally. Aside from all the fancy UI stuff they can do, it has really good cross-browser AJAX libraries.

$.get(
    "http://xyz.com/webservice.pl",
    { q : "google" },
    function(data) {
        alert(data);  // "google.com"
    }
);

How do I call a web service from javascript

2 Answers2

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