MySQL CREATE USER with a variable?

Question

I'd like to do this:

#Variables
SET @username="jdoe", @password="secret";

# Insert a new MySQL User
CREATE USER @username@'localhost' IDENTIFIED BY @password;GRANT USAGE ON *.* TO @username@'localhost' IDENTIFIED BY @password WITH MAX_QUERIES_PER_HOUR 120 MAX_CONNECTIONS_PER_HOUR 60 MAX_UPDATES_PER_HOUR 60 MAX_USER_CONNECTIONS 2;

But get:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@username@'localhost' IDENTIFIED BY @password' at line 2

How do I use a variable in the CREATE USER statement?

possible duplicate of [syntax error from CREATE USER with variables giving username and password](http://stackoverflow.com/questions/11368966/syntax-error-from-create-user-with-variables-giving-username-and-password) — aleroot, Aug 14 '12 at 12:12
@aleroot I'm not sure that's the same issue since it concerns creating a stored procedure. — Nick, Aug 14 '12 at 12:19

Omesh · Accepted Answer · 2012-08-14T12:35:47.097

17

You can use dynamic SQL as:

SET @query1 = CONCAT('
        CREATE USER "',@username,'"@"localhost" IDENTIFIED BY "',@password,'" '
        );
PREPARE stmt FROM @query1; EXECUTE stmt; DEALLOCATE PREPARE stmt;

SET @query1 = CONCAT('
    GRANT USAGE ON *.* TO "',@username,'"@"localhost" IDENTIFIED BY "',@password,'" WITH
          MAX_QUERIES_PER_HOUR 120 MAX_CONNECTIONS_PER_HOUR 60 MAX_UPDATES_PER_HOUR 60 
          MAX_USER_CONNECTIONS 2'
        );
PREPARE stmt FROM @query1; EXECUTE stmt; DEALLOCATE PREPARE stmt;

edited Aug 14 '12 at 12:35

answered Aug 14 '12 at 11:48

Omesh

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This doesn't seem to be working... I get `#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'secret; GRANT USAGE ON *.* TO jdoe@'localhost' IDENTIFIED BY secret ' at line 1 ` – Nick Aug 14 '12 at 11:56

MySQL CREATE USER with a variable?

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