Java BigDecimal without E

Question

I have a BigDecimal variable

BigDecimal x = new BigDecimal("5521.0000000001");

Formula:

x = x.add(new BigDecimal("-1")
      .multiply(x.divideToIntegralValue(new BigDecimal("1.0"))));

I want to remove the integer part, to get the value x = ("0.0000000001"), but my new value is 1E-10 and not the 0.0000000001.

1e-10 is 0.0000000001, so it's just a matter of presentation. — Paul Tomblin, Aug 19 '12 at 12:52
Try [toPlainString()](http://docs.oracle.com/javase/7/docs/api/java/math/BigDecimal.html#toPlainString()). — Keppil, Aug 19 '12 at 12:55

score 23 · Answer 1 · answered Aug 19 '12 at 13:18

To get a String representation of the BigDecimal without the exponent part, you can use
BigDecimal.toPlainString(). In your example:

BigDecimal x = new BigDecimal("5521.0000000001");
x = x.add(new BigDecimal("-1").
              multiply(x.divideToIntegralValue(new BigDecimal("1.0"))));
System.out.println(x.toPlainString());

prints

0.0000000001

score 3 · Answer 2 · answered Oct 06 '17 at 06:06

3

Try using BigDecimal.toPlainString() to get value as plain string as you require.

answered Oct 06 '17 at 06:06

Akhilesh Awasthi

2,688
4
21
30

score 2 · Answer 3 · answered Aug 20 '12 at 20:06

2

Perhaps using BigDecimal isn't really helping you.

double d = 5521.0000000001;
double f = d - (long) d;
System.out.printf("%.10f%n", f);

prints

0.0000000001

but the value 5521.0000000001 is only an approximate representation.

The actual representation is

double d = 5521.0000000001;
System.out.println(new BigDecimal(d));
BigDecimal db = new BigDecimal(d).subtract(new BigDecimal((long) d));
System.out.println(db);

prints

5521.000000000100044417195022106170654296875
1.00044417195022106170654296875E-10

I suspect whatever you are trying to is not meaningful as you appear to be trying to obtain a value which is not what you think it is.

answered Aug 20 '12 at 20:06

Peter Lawrey

525,659
79
751
1,130

so when System.out.println(bd);, I assume that's printing the .toString() representation, not .toPlainString() – Alexander Mills Feb 02 '15 at 01:45
@AlexMills println always calls the toString () even for String I believe. – Peter Lawrey Feb 02 '15 at 07:49

Antonio Giordano · Answer 4 · 2017-11-07T11:45:18.327

If you want to do this at your BigDecimal object and not convert it into a String with a formatter you can do it on Java 8 with 2 steps:

stripTrailingZeros()
if scale < 0 setScale to 0 if don't like esponential/scientific notation

You can try this snippet to better understand the behaviour

BigDecimal bigDecimal = BigDecimal.valueOf(Double.parseDouble("50"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
if (bigDecimal.scale()<0)
bigDecimal= bigDecimal.setScale(0);
System.out.println(bigDecimal);//50
bigDecimal = BigDecimal.valueOf(Double.parseDouble("50.20"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
if (bigDecimal.scale()<0)
bigDecimal= bigDecimal.setScale(0);
System.out.println(bigDecimal);//50.2
bigDecimal = BigDecimal.valueOf(Double.parseDouble("50"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
System.out.println(bigDecimal);//5E+1
bigDecimal = BigDecimal.valueOf(Double.parseDouble("50.20"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
System.out.println(bigDecimal);//50.2

Java BigDecimal without E

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