Haskell can this:
['a'..'z']
In Python:
map(chr, range(97, 123))
I feel Python is something verbose. Have Python another easy way like Haskell?
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This construct is common in Perl and it is addictive. I wish Python had it... – the wolf Aug 20 '12 at 04:08
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Verbose is not necessarily a bad thing. Although I wouldn't call that verbose. A clearer way to right that would be `[chr(i) for i in range(97, 123)]`. – Joel Cornett Aug 20 '12 at 04:08
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Also I believe ruby has this as well. – Joel Cornett Aug 20 '12 at 04:08
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In Perl, it is the [range operators](http://perldoc.perl.org/perlop.html#Range-Operators). Very addictive. – the wolf Aug 20 '12 at 04:13
5 Answers
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from string import ascii_lowercase
L = list(ascii_lowercase)
Dair
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@J.F.Sebastian: Oh, woops, funny I was testing it on my computer doing some slightly different code and that's why it didn't work for me on Python 3 xD – Dair Aug 20 '12 at 03:59
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A slightly more readable version without importing anything
alphabet = [chr(i) for i in range(ord('a'), ord('z') + 1)]
gsk
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There is no generic way, because syntax [a..b] in haskell uses special typeclass Enum, but there is no special magic methods or special syntax for enumeration in python.
Fedor Gogolev
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Also, although I can think of *some* uses for this syntax, most potential use cases are completely covered by `range(start, stop, step)` in python. – Joel Cornett Aug 20 '12 at 04:03
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Since you want it as a list, then you can do the following:
from string import ascii_lowercase
l = [i for i in ascii_lowercase]
Makoto
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