JavaScript check many keywords in some text?

Question

Please, whats the best way for checking if some text sentence have some of the keywords provided, and there could be 100 keywords.

For example:

var text = "Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.";
var keywords = ["lorem", "sit", "elit", "sed do"];

Now whats the best and fastest way to check if any of keywords is in text, but like whole word not part of word, and its case-insensitive?

BTW Its Google Script, maybe there is some function which I didnt see :\

Thanks in advance

André Silva · Answer 1 · 2012-08-28T12:15:23.600

3

for(var i = 0; i <= keywords. length - 1; i++) {
  var a = new RegExp('\\b' + keywords[i] + '\\b', 'gi');
  if(a.test(text)) {
    alert('Match ! - ' + keywords[i]);
  }
}

edited Aug 28 '12 at 12:15

answered Aug 28 '12 at 11:28

André Silva

1,149
9
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your script is good but you forget this: `"\\b" + keywords[i] + "\\b"` to match whole word. – Ghassan Elias Aug 28 '12 at 11:42
I didn't forget, I did it on purpose because I thought he was willing to match `abc` in `abcde` too. But it is still not wrong, at least can give him a start path. – André Silva Aug 28 '12 at 12:00
1

i know it's not wrong :) but he wanted to search and match the whole word as he mentioned in his question. – Ghassan Elias Aug 28 '12 at 12:08
Going to edit. I'm sorry about my lack of attention, so hard to answer stuff with boss walking around. Thanks for the heads up. :) – André Silva Aug 28 '12 at 12:14

Ghassan Elias · Answer 2 · 2012-08-28T11:40:14.100

2

var text = "Lorem Ipsumdolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.";
var keywords = ["Lorem", "ipsum", "not there", "Sed do"];

for (var i in keywords) {
    var index = new RegExp("\\b" + keywords[i] + "\\b", "i");
    if (text.match(index)) {
        alert(keywords[i]);
        // do something
    }
}

edited Aug 28 '12 at 11:40

answered Aug 28 '12 at 11:28

Ghassan Elias

2,213
1
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17

score 2 · Accepted Answer · edited May 23 '17 at 12:20

2

Try something on these lines.

var text = "Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.";
var keywords = ["lorem", "sit", "elit", "sed do"];
var words = text.split(/[\s,]+/); //Add all other delimiters you want to include. 
for(var i in words){ 
   words[i] = words[i].toLowerCase(); 
}
for(var i in keywords){
  if(words.indexOf(keywords[i].toLowerCase()) != -1){
    Logger.log('Match found for ' + keywords[i]);
    break;
  }
}

Thanks to this post for splitting on multiple delimiters

edited May 23 '17 at 12:20

Community

1
1

answered Aug 28 '12 at 11:33

Srik

7,907
2
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fix the syntax errors. `var keywords = ["lorem","etc.."]` and `if(words.indexOf(keywords[i].toLowerCase()) != -1){` – Ghassan Elias Aug 28 '12 at 11:56

score 0 · Answer 4 · answered Aug 29 '12 at 15:01

This code will be vastly more efficient if you use an object to store the keywords rather than an array.

var text = "Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.";
var keywords = {"lorem" : 1, "sit": 1, "elit" : 1, "sed do" : 1};
var words = text.split(/[\s,]+/); //Add all other delimiters you want to include. 
for(var i in words) { 
   if (keywords[words[i].toLowerCase()]) { 
     Logger.log('Match found for ' + keywords[i]);
     break;
  }
}

JavaScript check many keywords in some text?

4 Answers4