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To open a URL from a .NET application, many sites (including on StackOverflow) cite this example:

Process.Start("http://www.google.com/");

On Windows 8, this works if Internet Explorer is the default browser. However if Google Chrome is the default, it fails with:

Unhandled Exception: System.ComponentModel.Win32Exception: Class not registered

Does this suggest that this method is no longer the right way to open URL's on Windows? What alternatives exist? Is it safer to just launch Internet Explorer directly?

Community
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Paul Stovell
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5 Answers5

27

You may try to specify the Process filename "explorer.exe" explicitly, like suggested in the following thread:

http://social.msdn.microsoft.com/Forums/nl-BE/toolsforwinapps/thread/e051a102-469e-4ede-882c-c2c89377652a

var startInfo = new ProcessStartInfo("explorer.exe", url);
Process.Start(startInfo);
Armin
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    When the url contains special characters, like `=`, then it need to be quoted: `Process.Start("explorer.exe", $"\"{url}\"");` – xmedeko Dec 05 '17 at 12:48
1

Use the Launcher object to open URLs.

Example:

await Launcher.LaunchUriAsync(new Uri("www.google.com"));
1

I've tried many a solution but as i'm in a UI project (wpf or winform) I ended up using an embedded browser control. Calling navigate, setting the url then target to "_blank" launches an external browser window.

_webBrowser.Navigate(uri, "_blank");

Hope this helps. DC

David Christiansen
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0

The only robust solution I've found to this problem is described here: https://web.archive.org/web/20160304114550/http://www.seirer.net/blog/2014/6/10/solved-how-to-open-a-url-in-the-default-browser-in-csharp

Basically, you need to look through the Windows registry to find what the selected default browser is, and launch that directly as the process with the URL as the argument.

Cogwheel
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0

VB.Net alternative:

    Public Sub URLOpen(Url As String)

       Dim OpenURL As New ProcessStartInfo With {
        .UseShellExecute = True,
        .FileName = "explorer.exe",
        .Arguments = Url
       }

       Process.Start(OpenURL)

    End Sub
Arvy
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