Java compile error: cannot find symbol

Question

Hey I'm just starting my first programming book on java so this should be an easy fix. Messing around with my fresh knowledge of conditionals and I'm getting the title error.

Here's the code:

import java.util.Scanner;

public class Music
{
    public static void main( String[] args )
    {

        Scanner x = new Scanner( System.in );

        int y;

        System.out.print( "Which is better, rap or metal? 1 for rap, 2 for metal, 3 for neither" );
        y = input.nextInt();

        if ( y == 1 )
            System.out.print( "Someone hasn't heard\nhttp://www.youtube.com/watch?v=Vzbc4mxm430\nyet" );

        if ( y == 2 )
            System.out.print( "Someone hasn't heard\nhttp://www.youtube.com/watch?v=s4l7bmTJ7j8\nyet" );

        if ( y == 3 )
            System.out.print( "=/ \nMusic sucks anyway." );
    }
}

When I try to compile:

Music.java:13: error: cannot find symbol
y = input.nextInt();



symbol: variable input
location: class Music
1 error

+1 Don't understand why someone would -1 this complete question. — HeatfanJohn, Sep 02 '12 at 15:32

score 17 · Accepted Answer · answered Sep 02 '12 at 15:31

17

The error message is telling you that your variable 'input' doesn't exist in your scope. You probably want to use your Scanner object, but you named it 'x', not 'input'.

Scanner input = new Scanner( System.in );

Should fix it.

answered Sep 02 '12 at 15:31

Neal

6,722
4
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31

Reimeus · Answer 2 · 2014-03-27T20:59:27.400

8

You have not defined the variable input here. You should have:

Scanner input = new Scanner( System.in );

edited Mar 27 '14 at 20:59

answered Sep 02 '12 at 15:31

Reimeus

158,255
15
216
276

Same thing on my answer. I wish I knew why. – Derek W Mar 27 '14 at 21:06

score 2 · Answer 3 · answered Sep 02 '12 at 15:33

2

You used the variable input, as in

y=input.nextInt();

You can't do this, because it's not a variable. I believe you meant for it to be "x", or you could replace

Scanner x = new Scanner( System.in );

with

Scanner input = new Scanner( System.in );

answered Sep 02 '12 at 15:33

natewelch_

254
1
12

Derek W · Answer 4 · 2014-03-27T21:17:06.893

2

Alternatively, you could just change:

y = input.nextInt();

To:

y = x.nextInt();

Then it will work.

This is because input is not defined anywhere in the code. The provided code suggests that you expect it to be an instance of the Scanner class. But the instance of Scanner class is actually defined as x and not input.

edited Mar 27 '14 at 21:17

answered Sep 02 '12 at 15:56

Derek W

9,708
5
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karthik · Answer 5 · 2013-04-25T09:30:16.340

0

 Scanner x = new Scanner( System.in ); 
 int y = x.nextInt();

edited Apr 25 '13 at 09:30

answered Apr 20 '13 at 06:05

karthik

137
4

score 0 · Answer 6 · edited Oct 31 '13 at 09:09

0

Scanner input = new Scanner( System.in );
int y = input.nextInt();

(or)

Scanner x = new Scanner( System.in ); 
int y = x.nextInt();

edited Oct 31 '13 at 09:09

IvanH

5,039
14
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answered Oct 31 '13 at 08:50

sakthi

1

A bit more explanation would be useful. – IvanH Oct 31 '13 at 09:15

score -2 · Answer 7 · answered Mar 05 '15 at 19:37

-2

this is the simple fix y = x.nextInt(); instead of y = input.nextInt();

answered Mar 05 '15 at 19:37

Kirk

1

4

The question was adequately answered two minutes after it was posted *more than two years ago*. You're not adding anything new here now. – nobody Mar 05 '15 at 19:56

Java compile error: cannot find symbol

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