How to get a model object using model name string in Django

Question

Desciption:

I have a generic function

def gen(model_name,model_type): 
      objects = model_name.objects.all()
      for object in objects:
          object.model_type = Null      (Or some activity)
          object.save()

How Can I achieve the above ? Is it possible?

score 43 · Accepted Answer · answered Sep 05 '12 at 14:41

43

I would use get_model:

from django.db.models import get_model

mymodel = get_model('some_app', 'SomeModel')

answered Sep 05 '12 at 14:41

Chris Pratt

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2

Hi. I get an error that says `Cannot import name get_model` in the first line. Did anything change in the latest Django version? – Y2H May 30 '17 at 09:49
4

@Y2H yes, look here: https://stackoverflow.com/questions/4881607/django-get-model-from-string – Boris Paschenko Jul 26 '17 at 10:41

score 26 · Answer 2 · edited Jan 08 '16 at 07:55

As of Django 1.7 the django.db.models.loading is deprecated (to be removed in 1.9) in favor of the the new application loading system. The 1.7 docs give us the following instead:

$ python manage.py shell
Python 2.7.6 (default, Mar  5 2014, 10:59:47)
>>> from django.apps import apps
>>> User = apps.get_model(app_label='auth', model_name='User')
>>> print User
<class 'django.contrib.auth.models.User'>
>>>

score 4 · Answer 3 · answered Sep 05 '12 at 10:58

if you pass in 'app_label.model_name' you could use contenttypes e.g.

from django.contrib.contenttypes.models import ContentType

model_type = ContentType.objects.get(app_label=app_label, model=model_name)
objects = model_type.model_class().objects.all()

score 0 · Answer 4 · answered Sep 18 '14 at 19:37

0

The full answer for Django 1.5 is:

from django.db.models.loading import AppCache

app_cache = AppCache()
model_class = app_cache.get_model(*'myapp.MyModel'.split('.',1))

answered Sep 18 '14 at 19:37

jacob

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How to get a model object using model name string in Django

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