How to read a CSV string into an array

Question

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How can I split a comma delimited string into an array in PHP?
extract tags (words) from whole string

I'm trying to read a long variable into an array.

Variable $x = "text1", "text2", "text3", etc...

$x = '"text1", "text2", "text3"';

Do I just call it into my array like:

array($x)?

This doesn't seem to work

I want the final product to be:

array("text1", "text2", "text3")

What am I doing wrong? Thanks!

EDIT:

Ok, some specifics:

I'm trying to replace the date fields in the following array with many dynamically read dates:

$myCalendar->setSpecificDate(array("2012-09-09", "2012-09-10"), 1, '');

I have the dynamically read dates in a variable $x. When I echo $x, I get something in the format "2012-09-09", "2012-09-10", "2012-09-09", "2012-09-10", "2012-09-09", "2012-09-10", etc

Thanks

Why do you wanna do this way? I mean, giving commas is a non standard way right? — Praveen Kumar Purushothaman, Sep 05 '12 at 17:37
@SteveRobbins Not only in PHP. In all the langs this is not standard. — Praveen Kumar Purushothaman, Sep 05 '12 at 17:38
I am creating a variable from a very long process (that checks if files exist in directories. I'm trying to read those file names, surrounded by quotes, into an array. — user1569034, Sep 05 '12 at 17:39
$x= "text1 ,text2 ,text3"; ? what is correct variable initiation? — Yuseferi, Sep 05 '12 at 17:46

Brett · Accepted Answer · 2012-09-05T17:43:32.060

2

If your variable is a string like:

$x = '"text1", "text2", "text3"'

You can convert it to an array with str_getcsv like the following:

$x = '"text1", "text2", "text3"';
$yourArray = str_getcsv($x);

edited Sep 05 '12 at 17:43

answered Sep 05 '12 at 17:41

Brett

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Ruan Mendes · Answer 2 · 2012-09-05T17:49:42.777

1

If your input string is '"text1", "text2", "text3"'

You can use the following code to get an array with three string

print_r( 
   explode( ",", preg_replace('/[" ]*/', "", '"text1", "text2", "text3"'))
);
// Outputs Array ( [0] => text1 [1] => text2 [2] => text3 )

This assumes there are no spaces in your strings, you'll have to play with it if spaces are allowed

edited Sep 05 '12 at 17:49

answered Sep 05 '12 at 17:38

Ruan Mendes

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understood, but how do I get the "text1", "text2", etc out of the variable and into the array? – user1569034 Sep 05 '12 at 17:40
@Downvoters: This was posted before the answer was changed to make sense... – Ruan Mendes Sep 05 '12 at 17:43
@JuanMendes If people do not remove their downvotes or just they don't let you know why, just delete the answer. As far our answers are correct... – Praveen Kumar Purushothaman Sep 05 '12 at 17:44
@PraveenKumar I can't tell what you mean... but the answer has been updated to match the question as it stands – Ruan Mendes Sep 05 '12 at 17:50
Right, the downvoters have voted down and went off. We can't even find who they are to call and ask them to upvote, or at least remove the down votes right? – Praveen Kumar Purushothaman Sep 05 '12 at 17:51
Even though we are right and in the good sense, helping someone, we are getting penalized for nothing! – Praveen Kumar Purushothaman Sep 05 '12 at 17:51
@user1569034 My answer does work with your edit, for people who don't have PHP >=5.3 – Ruan Mendes Sep 05 '12 at 17:59
+1 Juan - I understand the annoyance of down-votes when they are not warranted. – xil3 Feb 19 '13 at 19:08

score 0 · Answer 3 · answered Sep 05 '12 at 17:41

0

Explode it. String becomes an array based on a delimiter.

$x = "text1,text2,text3";
$new_array = explode(',', $x);

This becomes:

Array
(
    [0] => text1
    [1] => text2
    [2] => text3
)

answered Sep 05 '12 at 17:41

wesside

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How to read a CSV string into an array

3 Answers3

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