Pass PHP variable to javascript src

Question

Okay, so I have a php variable which stores:

http://gdata.youtube.com/feeds/api/videos/gzDS-Kfd5XQ?v=2&alt=json-in-script&callback=youtubeFeedCallback

This is working fine and i want to do the following:

<script type="text/javascript" src="<?php echo $string; ?>"></script>

But it doesn't seem to be working

Thanks for any help

EDIT: Here is my code, tried all 3 answers below but didn't work: http://pastebin.com/xYKW8TTd

can you define not working? is it printing the link in source? — Nicholas King, Sep 06 '12 at 08:38
the link seems to work fine, but the file is a json data that must be received by a ajax or something(it depends on what you really want to do) — Netorica, Sep 06 '12 at 08:40

Fluffeh · Accepted Answer · 2012-09-06T08:54:53.003

This seems to work as expected:

<?php

    $string="http://gdata.youtube.com/feeds/api/videos/gzDS-Kfd5XQ?v=2&alt=json-in-script&callback=youtubeFeedCallback";

?>

<script type="text/javascript" src="<?php echo $string; ?>"></script>

with the output of:

<script type="text/javascript" src="http://gdata.youtube.com/feeds/api/videos/gzDS-Kfd5XQ?v=2&alt=json-in-script&callback=youtubeFeedCallback"></script>

Edit: in your source code on pastebin, you seem to have:

$string = "http://gdata.youtube.com/feeds/api/videos/" . $id ."?v=2&amp;alt=json-in-script&amp;callback=youtubeFeedCallback";

which contains & in the place of & which would stop the link working. Was this somethign that pastebin did or was it in your original code?

You can't send HTML codes to the URL window and expect it to work the same way as if it was in a HTML body.

The following code (just edited $id as I am not putting anything in GET and modified & symbols gave:

<html>
<head>
<?php
    //$id = $_GET['id'];
    $id=0;
    $string = "http://gdata.youtube.com/feeds/api/videos/" . $id ."?v=2&alt=json-in-script&callback=youtubeFeedCallback";
?>


<title></title>
</head>
<body>
<?php echo $string; ?><br>
<script type="text/javascript" src="<?php echo $string; ?>"></script>

Had the output of:

<title></title>
</head>
<body>
http://gdata.youtube.com/feeds/api/videos/0?v=2&alt=json-in-script&callback=youtubeFeedCallback<br>
<script type="text/javascript" src="http://gdata.youtube.com/feeds/api/videos/0?v=2&alt=json-in-script&callback=youtubeFeedCallback"></script>

I moved the scripts around and it worked. Thanks ever so much for your help. — user1641732, Sep 06 '12 at 09:10

score 0 · Answer 2 · answered Sep 06 '12 at 08:39

0

Try this:-

<?php
$str = 'http://gdata.youtube.com/feeds/api/videos/gzDS-Kfd5XQ?v=2&alt=json-in-script&callback=youtubeFeedCallback';
?>
<script type="text/javascript" src="<?php echo $str; ?>"></script>

answered Sep 06 '12 at 08:39

Abid Hussain

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Tried but didn't work, check my edit to see my code, thanks – user1641732 Sep 06 '12 at 08:50

score 0 · Answer 3 · answered Sep 06 '12 at 08:39

0

<?php
$string = 'http://gdata.youtube.com/feeds/api/videos/gzDS-Kfd5XQ?v=2&alt=json-in-script&callback=youtubeFeedCallback';
?>

<script type="text/javascript" src="<?=$string;?>"></script>

answered Sep 06 '12 at 08:39

elo

615
4
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Tried but didn't work, check my edit to see my code, thanks – user1641732 Sep 06 '12 at 08:49
You have : , here works ? – elo Sep 06 '12 at 08:59

rkosegi · Answer 4 · 2012-09-06T08:52:04.263

0

Try this:

echo "<script type=\"text/javascript\" src=\"".$string"\"></script>\n";

If this "does not work", you have some error in string constant which cause javascript error.

Please provide more info, like generated source or exact browser error.

UPDATE:

@user1641732 : As of Mahan's comment. You are including JSON object, not javascript.What you are try to achieve? Did you understand difference between JSON object and javscript code?

edited Sep 06 '12 at 08:52

answered Sep 06 '12 at 08:39

rkosegi

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Tried but didn't work, check my edit to see my code, thanks – user1641732 Sep 06 '12 at 08:47
@user1641732 : It Seems you don't understand, so once again.Post GENERATED HTML code, not source.Also, what you are expecting from your code? – rkosegi Sep 06 '12 at 08:50
I get a 500 internal server error with my string printed out on the page: – user1641732 Sep 06 '12 at 08:53
500 means internal server error, neither javascript nor PHP problem. – rkosegi Sep 06 '12 at 08:55
From experience this normally happens when there is an error in my php code. – user1641732 Sep 06 '12 at 08:58

score 0 · Answer 5 · answered Sep 06 '12 at 08:55

Why are you trying to do this? Surly the best way to retrieve data from YouTube would be to do a php cUrl request and decode the json data their, or alternatively, if you really have to you can save the contents to a file with file_put_contents or fopen.

Here is a cUrl example, add your own $url variable:

// get the data via curl
$ch = curl_init();
curl_setopt( $ch, CURLOPT_URL, $url );
curl_setopt( $ch, CURLOPT_ENCODING, "" );
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
curl_setopt( $ch, CURLOPT_CONNECTTIMEOUT, 10 );
curl_setopt( $ch, CURLOPT_TIMEOUT, 10 );
$rsp = json_decode(curl_exec($ch));
curl_close($ch);

score 0 · Answer 6 · edited Sep 06 '12 at 13:10

0

<?php
$string = "http://gdata.youtube.com/feeds/api/videos/gzDS-Kfd5XQ?v=2&alt=json-in-script&callback=youtubeFeedCallback";
?>

<script type="text/javascript" src="<?php echo $string; ?>"></script>

edited Sep 06 '12 at 13:10

Mike Mackintosh

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answered Sep 06 '12 at 09:59

zed Blackbeard

760
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Pass PHP variable to javascript src

6 Answers6