Curl returns 400 bad request (url with spaces)

Question

When i use curl library and try to get image from url i get 400 bad request error. I founded that problem is with encoding url. But in my case it's not work, because my url - it's path to image on server side - like

http://example.com/images/products/product 1.jpg

I understand that user spaces in name files it's bad practice, but it's not my server and not i created those files.

$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, urlencode($url));
echo $ret = curl_exec($ch);

When i use urlencode function - curl return http_code = 0

Updated

$url = str_replace(' ', '+', $url);

doesn't work, server return 404 error.

is such a URL possible ( with space ). Space turns into `%20` when we type space in URL — xkeshav, Sep 09 '12 at 19:26
@diEcho what? of course it is possible. It doesn't turn into %20 by itself - some clients can do that, but certainly not all of them, and always it isn't even possible. — eis, Sep 09 '12 at 19:34

score 28 · Accepted Answer · answered Sep 09 '12 at 19:30

28

Does this maybe work?

$url = 'http://host/a b.img';
$url = str_replace(" ", '%20', $url);

$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url);
echo $ret = curl_exec($ch);

answered Sep 09 '12 at 19:30

Wim Molenberghs

882
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score 2 · Answer 2 · edited May 23 '17 at 10:28

2

You need to use rawurlencode() function:

$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, rawurlencode($url));
echo $ret = curl_exec($ch);

rawurlencode() must be always preferred. urlencode() is only kept for legacy use. For more details look at this SO answer.

edited May 23 '17 at 10:28

Community

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answered Jan 20 '15 at 19:43

Alexander Yancharuk

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5
55
55

score 0 · Answer 3 · answered Sep 09 '12 at 19:21

0

You can't urlencode the entire string because that will encode the slashes and others that you need to remain unencoded. If spaces are your only problem, this will do:

str_replace(' ', '+', $url);

answered Sep 09 '12 at 19:21

Explosion Pills

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@yAnTar what is the resulting URL after `str_replace`? – Explosion Pills Sep 09 '12 at 19:28
I would to post really url, but parser on stackoverflow cut the symbols. I posted only filename real filename - Michal Dziekan 016-thumb-600x791-188072.jpg After replacing - Michal+Dziekan+016-thumb-600x791-188072.jpg – yAnTar Sep 09 '12 at 19:32
@techie_28 either one should work, but `%20` is more technically correct now. Go ahead and give that a try. – Explosion Pills Sep 09 '12 at 19:45
for me, '+' works fine, probably depends on the server – charlie Oct 09 '15 at 18:21

score -1 · Answer 4 · answered Jan 20 '22 at 11:50

Using curl has more challenges than other ways. Simply use shell_exec

$cmd = "curl -k -v -X POST 'https://serveraddress:8243/?foo=bar' -H 'Authorization: Basic cEZ.....h'";

$result = shell_exec($cmd);         
$output =  json_decode($result,true);
print_r($output);

Curl returns 400 bad request (url with spaces)

4 Answers4

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