Computation of string at run time and compile time

Question

I found that the constant literal is computed at compile time for example:int a=10+20; but when i try to use int b=10/0; i find that it is computed at run time. Can you please tell me why this constant literal is computed at run time? Thank you.

He is farseer, has a null talisman that allows divison by zero — huseyin tugrul buyukisik, Sep 11 '12 at 19:27
possible duplicate of [Is 1/0 a legal Java expression?](http://stackoverflow.com/questions/2934063/is-1-0-a-legal-java-expression) — Greg Hewgill, Sep 11 '12 at 19:28

score 3 · Accepted Answer · edited Sep 11 '12 at 19:45

3

A constant value MAY be computed at compile time, if the compiler can maintain the same semantics as if it were done at run time. If not (eg, the case of divide by zero) then it defers the computation to run time. For more info read JLS 15.28.

edited Sep 11 '12 at 19:45

Roger Lindsjö

11,330
1
42
53

answered Sep 11 '12 at 19:25

Hot Licks

47,103
17
93
151

Computation of string at run time and compile time

1 Answers1