Calling a function after another one has successfully ended

Question

I'd like to call a javascript (with jQuery) function after one has completely ended.

I know there's a way to do it using the $.ajax() function with the 'success:' parameter. Is there a way to do the same thing without using the $.ajax() function ?

For example if I had :

var test = function()
{
    alert('Hello !');
}

var test_check = function()
{
    alert('Hello has been displayed successfully');
}

Would there be a way to call test(); and then test_check() ONLY after test() has actually been completed ?

This heavily depends on your usage of asynchronous tasks. If you don't have anything async, just call your functions one after the other. If you are having async operations they will probably supply you with a callback parameter. — m90, Sep 12 '12 at 08:53
This might help:: http://stackoverflow.com/questions/1937970/run-another-function-after-preceding-function-has-completed — Sudhir Bastakoti, Sep 12 '12 at 08:54

score 1 · Answer 1 · answered Sep 12 '12 at 08:52

1

The function will return when it has completed, so you just call the next function after it:

test();
test_check();

answered Sep 12 '12 at 08:52

Guffa

687,336
108
737
1,005

score 1 · Answer 2 · answered Sep 12 '12 at 08:53

1

var test = function()
{
    alert('Hello !');
    test_check(); /* call test_check() at the very end of test() */
}

answered Sep 12 '12 at 08:53

alexbusu

701
4
13

score 0 · Accepted Answer · edited Jul 26 '19 at 19:54

0

The following will work

test();
test_check();

test_check will execute after test finishes executing.

edited Jul 26 '19 at 19:54

buydadip

8,890
22
79
154

answered Sep 12 '12 at 08:54

Clyde Lobo

9,126
7
34
61

-1 That has nothing to do with the fact that Javascript is a single threaded language. The same applies to multi threaded languages also. – Guffa Sep 12 '12 at 11:12

Calling a function after another one has successfully ended

3 Answers3