Get contents form HttpRequest

Question

I am uploading a .war file in jsp as follows,

<input type="file" name="file1" id="file1" size="50">

example: C:\1234\OnlineBookStore.war

and uploading the form using ajax as follows,

var fileValue = document.getElementById("file1").value; 
url=url+"&fileName="+fileValue;
loadPage('downloaddiv', url);

when i get the filename in java i am just getting the name of the file(OnlineBookStore.war

) without its contents,

File uploadedFile = new File(request.getParameter("fileName"));

how to get the file with contents form request?

Thanks

Have you checked the answer to http://stackoverflow.com/questions/2422468/how-to-upload-files-to-server-using-jsp-servlet — Ashwin Prabhu, Sep 12 '12 at 10:36
http://stackoverflow.com/questions/10251758/how-to-upload-file-using-ajax — Ashwin Prabhu, Sep 12 '12 at 10:39

score 1 · Answer 1 · answered Sep 12 '12 at 10:33

You need to use the File API if you want to read the data from files to upload via XMLHttpRequest.

There is a guide to Using files from web applications on MDN.

Note that this requires a browser that supports this bleeding edge feature.

The classic way to upload files via Ajax is to submit a form to a hidden iframe.

score 0 · Answer 2 · edited May 23 '17 at 11:55

Maybe you should checkout this question: How to get the file path from HTML input form in Firefox 3

There is little to no reason why server should have to know full file path. If you want to upload a file, you'll need to use an appropriate library like Apache Commons FileUpload and transfer the file using.

<form action="upload-script-url" method="post" enctype="multipart/form-data">
  <input type="file" name="file">
  <input type="submit">
</form>

Apache Commons FileUpload will then accept and transform encoded file into a usable form.

Otherwise you'll need to use JavaScript to get that path.

Get contents form HttpRequest

2 Answers2