Unusual android logic operator not working comparing two strings

Question

I'm trying a simple check. If a string name locale has "es" as value.

public String locale = 
    Locale.getDefault().getLanguage().toLowerCase().toString();

// ...

Log.v(tag, "Idioma del sistema: «" + locale +"»");
if (locale != "es") {
    showDialog(R.string.warningTitleDialog, 
        "We are sorry that this tool is only available in Spanish " +
        "language. See Author menu item for more information. [" + 
        locale + "]");
    locale = "en";
}

adb logcat shows "es" as content of string "locale" but code inside the condition is being executed.

score 2 · Accepted Answer · answered Sep 13 '12 at 18:47

2

It seem that problem is not of android or of logic this is in JAVA. Try this and tell us what is happening

if(!locale.equals("en"))
{
   //Your Code
}

answered Sep 13 '12 at 18:47

jignesh Vadadoriya

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1

== and != operator compares the addresses – nandeesh Sep 13 '12 at 18:49
Yes and that's why he always get false. – jignesh Vadadoriya Sep 13 '12 at 18:52

score 2 · Answer 2 · edited May 23 '17 at 12:13

Never use != or == in association with strings. Try the method equals like this:

if(locale.equals("es"))

This will return true if the strings locale and "es" contain the same character sequence. Because the equals( ) method compares the characters inside a String object. The == operator compares two object references to see whether they refer to the same instance.

See What is the difference between == vs equals() in Java? for more information.

Unusual android logic operator not working comparing two strings

2 Answers2