How to get the position of the Item clicked on ContextMenu?

Question

I am using this code to get the Clicked Item position on the Context Menu:

public boolean onContextItemSelected(MenuItem item) {
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
    int index = info.position;
}

as suggested here:

Android: How to find the position clicked from the context menu

But i get NullPointerException at line:

 int index = info.position;

why is it so?

EDIT

I have 2 registered Views for the contextMenu like this:

button1.onClick(view v){
registerForContextMenu(v);
openContextMenu(v);
}

button2.onClick(view v){
registerForContextMenu(v);
openContextMenu(v);
}

then depending on v.getId() i populate the menu.

I definitely have items. and regarding registration, yeah i am doing, but then soon i am unregistered, for some reason. so thats the problem?? — Archie.bpgc, Sep 14 '12 at 12:48
But i removed unregister line. It still gives the same error — Archie.bpgc, Sep 14 '12 at 12:50

score 0 · Answer 1 · answered Sep 14 '12 at 12:49

0

See this tutorial http://www.stealthcopter.com/blog/2010/04/android-context-menu-example-on-long-press-gridview/

answered Sep 14 '12 at 12:49

Yahor10

2,123
1
13
13

Rushabh Patel · Accepted Answer · 2012-09-14T13:02:54.223

0

You can use directly:

EDITED BEGIN

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    AdapterView.AdapterContextMenuInfo info;
    try {
        info = (AdapterView.AdapterContextMenuInfo) menuInfo;
    } catch (ClassCastException e) {
        // If the menu object can't be cast, logs an error.
        Log.e("MENU", "bad menuInfo", e);
        return;
    }
    position = sectionAdapter.getIndexForPosition(info.position);
    menu.setHeaderTitle("");
    String[] menuItems = { "item1","item2","item3","item4" };
    for (int i = 0; i < menuItems.length; i++) {
        menu.add(Menu.NONE, i, i, menuItems[i]);
    }
}

EDITED END

public boolean onContextItemSelected(MenuItem item) {
    // TODO Auto-generated method stub
    int position = item.getItemId();
    switch (position) 
    {

        case 0:
        break;
        .
        .
        .
        default:
        break;
    }
}

Hope it will help you.

edited Sep 14 '12 at 13:02

answered Sep 14 '12 at 12:51

Rushabh Patel

3,052
4
26
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getItemId() returns the position??are you sure? – Archie.bpgc Sep 14 '12 at 12:53
yes i have used it...it will give you position of the context menu's item – Rushabh Patel Sep 14 '12 at 12:56
Its giving value 0 for every item i clicked. What might be wrong?? – Archie.bpgc Sep 14 '12 at 12:57
Have you register context menu using registerContextMenu()...? – Rushabh Patel Sep 14 '12 at 13:05
i am checking the value of info just after this step: "info = (AdapterView.AdapterContextMenuInfo) menuInfo;" it gives null – Archie.bpgc Sep 14 '12 at 13:07
I tried your edited code. there is no exception, but then i get null for info in the try block – Archie.bpgc Sep 14 '12 at 13:09
for me it works perfectly this same code. now try by removing your code "openContextMenu(v);" line in edit section. – Rushabh Patel Sep 14 '12 at 13:11
1 thing. should i register just after getting the view from the resource. because what i am doing in my code is. on this view clicked i register and open the contextmenu – Archie.bpgc Sep 14 '12 at 13:17
then do one thing try without registering the context menu and also refer this [link](http://stackoverflow.com/questions/5645235/android-opening-context-menu-after-button-click) – Rushabh Patel Sep 14 '12 at 13:26
i am getting item name correctly if i am using item.toString(). But item id i am getting 0 for all of them and item.getMenuInfo() gives null – Archie.bpgc Sep 14 '12 at 13:27
yeah, even i might end up using dialogs, but i just want to know the reason i get this issue – Archie.bpgc Sep 14 '12 at 13:28

How to get the position of the Item clicked on ContextMenu?

2 Answers2