scala varargs (Any*) wrapped twice

Question

  def main(args: Array[String]) {
      foo("hello")
  }

  def foo(args:Any*){
    bar(args)
  }

  def bar(args:Any *){
    println(args)
  }

Look the code above, the output is WrappedArray(WrappedArray(hello))

The String 'hello' is wrapped twice, how to avoid this

score 5 · Accepted Answer · answered Sep 16 '12 at 09:01

5

In the invocation of bar, write this:

bar(args: _*)

This tells the compiler to use the args in args, which at this point is very similar to a Seq[T], and pass each of them separately to bar, instead of considering args as the first of the repeated parameters that bar accepts.

answered Sep 16 '12 at 09:01

Jean-Philippe Pellet

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could you make some explanation? – jilen Sep 16 '12 at 09:02
@jilen This answer covered the topic fairly well: http://stackoverflow.com/questions/4176440/syntax-sugar – Leif Wickland Sep 16 '12 at 09:11

scala varargs (Any*) wrapped twice

1 Answers1