What does this 4 line java code means in android application?

Question

In my java application i have this code

@Override
public void onAttachedToWindow()
  {
  this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD_DIALOG);
  super.onAttachedToWindow();
  }

when i build it for android 2.3 (level 10) it compiles and works fine. But when i build it for android 4.0 (level 15) it compiles and gives me crash at run time and following error

07-16 14:00:03.090: E/AndroidRuntime(29487): FATAL EXCEPTION: main
07-16 14:00:03.090: E/AndroidRuntime(29487): java.lang.IllegalArgumentException: Window type can not be changed after the window is added.

when i comment this line and build it works fine and no issue..

//this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD_DIALOG);

so i am not getting why this happning and whats this code means?

Edit : some reference are here

when I run app on my phone.The version is android 4.0.3

toddler safe app on android

It simply means when your activity comes to foreground like onDisplay in blackberry — Hitesh Jain, Sep 24 '12 at 07:15
Simply set targetSDK to less then 14 . Then it will work http://stackoverflow.com/a/32587231/3496570 — Zar E Ahmer, Sep 15 '15 at 13:22

score 9 · Accepted Answer · answered Oct 15 '12 at 07:07

9

@Override
public void onAttachedToWindow()
  {
  this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD_DIALOG);
  super.onAttachedToWindow();
  }

is used to disable home button in android but

this security flaw has been fixed in newer versions of Android so it will not work in ICS and jelly bean...!!

answered Oct 15 '12 at 07:07

Jeegar Patel

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It's giving me the error that java.lang.IllegalArgumentException: Window type cannot be changed after the window is added. – B.shruti Apr 05 '19 at 06:39

score 4 · Answer 2 · answered Nov 14 '13 at 18:26

I've solved this issue putting

this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD_DIALOG);

in onCreate before calling super.

 protected void onCreate(Bundle savedInstanceState) {

        this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD_DIALOG);

        super.onCreate(savedInstanceState);
}

Saludos desde Medellín

score 2 · Answer 3 · answered Sep 24 '12 at 07:02

@Override    
public void onWindowFocusChanged(boolean hasFocus) {
    this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD_DIALOG);    
    super.onWindowFocusChanged(hasFocus);
}

I had some problems with windowAttached as well, try using windowFocusChanged instead.

What does this 4 line java code means in android application?

3 Answers3

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