How to fix "Strict Standards: Only variables should be passed by reference"?

Question

Can someone please help me with these 4 lines of code. I been trying to read how to fix this error but I'm not very familiar with php that much yet.

$currentFile = $_SERVER["SCRIPT_NAME"];
$img = array_pop(explode("/", $currentFile));
$fileName = basename($img, ".php").PHP_EOL;
echo $fileName;

This script finds the current $.php name and spits it out. It also cuts the location of the file and the extension as well... leaving just the fileName.

How would I write these 4 lines of code to not throw that Strict Standard error

Don't know how, or where to put it. I know, I'm bad... sorry! — user1707535, Sep 30 '12 at 08:16
possible duplicate of [Strict Standards: Only variables should be passed by reference](http://stackoverflow.com/questions/2354609/strict-standards-only-variables-should-be-passed-by-reference) — Lorenz Meyer, Jun 21 '14 at 08:31

score 2 · Answer 1 · answered Sep 30 '12 at 08:16

2

Just add a varible.

$currentFile = $_SERVER["SCRIPT_NAME"];
$ret = explode("/", $currentFile);
$img = array_pop($ret);
$fileName = basename($img, ".php").PHP_EOL;
echo $fileName;

But you could just use basename only, the below code will give you same result:

$fileName = basename($_SERVER["SCRIPT_NAME"], ".php").PHP_EOL;

answered Sep 30 '12 at 08:16

xdazz

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Wow, how do you guys know all this. Thanks, and also thanks for shortening the code. – user1707535 Sep 30 '12 at 08:21

How to fix "Strict Standards: Only variables should be passed by reference"?

1 Answers1