List copied files in bash

Question

I need to copy files from one directory to another (pretty obvious :) ) but I want to store list of files that were copied with destination path. So let's say I have: /mnt/a/f1 /mnt/a/f2

and I want to copy all files from 'a' to root so I do: cp -rv /mnt/a/* /

output from cp I will have will look like:

`/mnt/a/f1` -> `/f1`

`/mnt/a/f2` -> `/f2`

and now I want to store in some file list that will looks like:

/f1

/f2

Does somebody know how can I achieve such output?

score 4 · Accepted Answer · answered Oct 01 '12 at 08:35

4

cp -rv /mnt/a/* / 2>&1 | cut -d\` -f4 | tee thefile.txt

Something like this (untested).

answered Oct 01 '12 at 08:35

Michael Krelin - hacker

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Great! Thanks! Works almost fine, I put wrong output format (for cp) so here is slightly corrected solution: cp -rv mnt/a/ / 2>&1 | cut -d\` -f3 | cut -d\' -f1 | tee thefile.txt – tomekK Oct 01 '12 at 08:45
Ah, I see. Yes, my `cut` was based on your output, but glad you figured it. – Michael Krelin - hacker Oct 01 '12 at 08:47

score 0 · Answer 2 · edited May 23 '17 at 10:24

You can simply use something like

cp -rv files dest > output_file

and redirect all the output to a file, but if you absolutely need to split it so you only have the ending I would recommend writing something quickly in Ruby, Python, or Perl and just symlink it as something like "verbose_cp". If you really want to you can do the splitting in Bash, though in my opinion doing it in languages with stronger string handling would be much easier.

List copied files in bash

2 Answers2