XML request/response in Java

Question

I have an API which I want to use to fetch data. For fetching data I have to send a request in XML format and response will be sent in XML. Does anyone have any example how to send a request using Java and how to decode the response in java.

Your question is too vague as for me... Are you talking about web services? What API is based on? Maybe its just an http connection to soe servlet? Please elaborate a little — Mark Bramnik, Oct 01 '12 at 17:16
Could you be a little more specific on how you want to send a request via XML? It can be done by POST, SOAP, AIM SIM etc... And to what - web service, web page.. Checkout the javax.xml.soap package — Ben Sewards, Oct 01 '12 at 17:17
@BenSewards POST ..I have a URL for the application and it accepts POST requests in XML format. — yogsma, Oct 01 '12 at 17:20
@yogsma you can use the OutputStreamWriter for sending a POST requesting using a URL: http://www.exampledepot.com/egs/java.net/post.html — Ben Sewards, Oct 01 '12 at 17:25

score 2 · Accepted Answer · answered Oct 01 '12 at 17:28

Well i have just what you wanted... but i would ask you to use the following APIs ...

JAXP and JAXB
Castor

- The below code snippet method accepts the url of the web-server and the xmlQuery

- I have used the NameValuePair to send the XML request

- Please replace the MySSLSocketFactory.getNewHttpClient(); with an Http Client, i have used this it needs a custom certificate to access this site.`

Here is the code from my Project, that sends an XML req and gets back an XML resp :

public String postData(String url, String xmlQuery) {

        final String urlStr = url;
        final String xmlStr = xmlQuery;
        final StringBuilder sb = new StringBuilder();

        Thread t1 = new Thread(new Runnable() {

            public void run() {

                HttpClient httpclient = MySSLSocketFactory.getNewHttpClient();

                HttpPost httppost = new HttpPost(urlStr);

                try {

                    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(
                            1);
                    nameValuePairs.add(new BasicNameValuePair("xml", xmlStr));

                    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                    HttpResponse response = httpclient.execute(httppost);

                    Log.d("Vivek", response.toString());

                    HttpEntity entity = response.getEntity();
                    InputStream i = entity.getContent();

                    Log.d("Vivek", i.toString());
                    InputStreamReader isr = new InputStreamReader(i);

                    BufferedReader br = new BufferedReader(isr);

                    String s = null;

                    while ((s = br.readLine()) != null) {

                        Log.d("YumZing", s);
                        sb.append(s);
                    }

                    Log.d("Check Now", sb + "");

                } catch (ClientProtocolException e) {

                    e.printStackTrace();
                } catch (IOException e) {
                    e.printStackTrace();
                } 
            }

        });

        t1.start();
        try {
            t1.join();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        System.out.println("Getting from Post Data Method " + sb.toString());

        return sb.toString();
    }

score 0 · Answer 2 · edited May 23 '17 at 10:24

0

Have a look at the following discussion, How to send HTTP request in java? For the response in xml, make sure that the mime-type is set to application/xml. Hope this answers your question.

edited May 23 '17 at 10:24

Community

1
1

answered Oct 01 '12 at 17:20

Arham

2,072
2
18
30

XML request/response in Java

2 Answers2