I'm trying to pass a 2D array of char* into a function. I am getting this error:
"cannot convert 'char* (*)[2]' to 'char***' for argument '1' to 'int foo(char***)'"
Code:
int foo(char*** hi)
{
...
}
int main()
{
char* bar[10][10];
return foo(bar);
}
Your array is an array of 10 char* arrays, each storing 10 char* pointers.
This means that when passing it to a function whose parameter is not a reference, it is converted to a pointer to an array of 10 char*. The correct function parameter type is thus
int foo(char* (*hi)[10])
{
...
}
int main()
{
char* bar[10][10];
return foo(bar);
}
Read further on this Pet peeve entry on Stackoverflow.
If the size of your array is not going to change, you're better off using references to the array in your function. Its safer and cleaner. For example:
int foo(char* (&hi)[10][10] )
{
int return_val = 0;
//do something
//hi[5][5] = 0;
return return_val;
}
int main()
{
char* bar[10][10];
return foo(bar);
}
Would this be a bad time to introduce the concept of references?
Off hand, I would say that an extra '&' would be needed on the calling side. That being said, this is a dangerous game to play.
Why are you allocating this? Why is it on the stack? Why are you typing it to a char*** in the receiving function?
Jacob
try
int foo(char* hi[10][10])
{
}
int main()
{
char* bar[10][10];
return foo(bar);
}
Alternatively, use a reference, a vector of vectors or boost::multi_array.
