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I am working with HTML5, JavaScript, JQuery.

Brian Tompsett - 汤莱恩
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Flot2011
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2 Answers2

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There's an $.isNumeric() function in jQuery 1.7, otherwise you'll have to write your own function in Javascript - there's a few answers on that already.

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whostolemyhat
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I think your question is very similar to question but there might be a better answer. This following fiddle works for your case. I used the same code as in the mentioned question

$(document).ready(function() {
    $(".only-numbers").keydown(function(event) {
        // Allow: backspace, delete, tab, escape, and enter
         if ( event.keyCode == 46 || event.keyCode == 8 || event.keyCode == 9 || event.keyCode == 27 || event.keyCode == 13 || 
              // Allow: Ctrl+A
             (event.keyCode == 65 && event.ctrlKey === true) || 
             // Allow: home, end, left, right
             (event.keyCode >= 35 && event.keyCode <= 39)) {
             // let it happen, don't do anything
             return;
        }
        else {
            // Ensure that it is a number and stop the keypress
            if (event.shiftKey || (event.keyCode < 48 || event.keyCode > 57) && (event.keyCode < 96 || event.keyCode > 105 )) {
                event.preventDefault(); 
            }   
    }
});

});

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Jacob George
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