JS array to PHP

Question

I have an generated output.js file from a specific device which contains Array in it:

var OUT=new Array (0x80,0x00,0x40,0x0026,0x0011,0x0014,0x0013,0x0018,0x0017,0x03FD,0x0116)

How can i get access to this array with PHP, so i can easily print specified Array[x] in any location:

print $OUT[4];

With simple JS i was able to do it like:

document.write(OUT[4]);

In case i can also handle that output.js with PHP like a txt file and then splitting and "doing like array thing" but i think there is away to use it right.. ^_^

Any tips or suggestions on that ? :)

Thnx!

On my PHP page no, cuz i'm not so good at it yet. But it if it's needed to get what i want, i will. — 45RPM, Oct 06 '12 at 20:03

score 2 · Accepted Answer · edited May 23 '17 at 10:24

If you want to fetch the file directly with PHP then you can either write a custom parser (using regular expressions if you can trust the file format to be consistant) or by interfacing with a JavaScript engine.

Otherwise, assuming the JavaScript is running in a web browser…

The simplest way to do this would be to make use of createElement and appendChild while looping over an array to create a form element containing a hidden input for each element of the array (with a name such as foo[] to satisfy the algorithm PHP uses to populate $_POST and friends) and then submit() the form.

Alternatively, you could serialise the array to a string (e.g. a comma separated one if you know that there are no commas in the data) and create a query string with it (var qs = "?foo=" + encodeURIComponent(serialised_array);) and then pass it using XMLHttpRequest.

Thnx! `createElement` and `appendChild` Helped a lot! :) – 45RPM Oct 06 '12 at 21:32 — 45RPM, Oct 06 '12 at 21:32

score 0 · Answer 2 · answered Oct 06 '12 at 20:05

0

you can use json for doing this

var jsonString  = JSON.stringify(OUT);

then

document.getElementById('IdOfYourFormInputField').value = jsonString;

// make element type hidden

now when you submit the form you will get the json string in $_POST field

so you can decode it like

$phpArray = json_decode($_POST['NameOfYoutInputEleMent']);

That's It!!!

answered Oct 06 '12 at 20:05

Rupesh Patel

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What if it isn't used in a form? – Oct 06 '12 at 20:12
@ChristianNikkanen you can post it directly by ajax to your php file without using any form – Rupesh Patel Oct 06 '12 at 20:15

score 0 · Answer 3 · answered Oct 06 '12 at 20:32

Easiest way is to use a library like jQuery rather than roll your own...

<head>
<script src="http://code.jquery.com/jquery.min.js">
....

Then at the point you calculate your data, post it to PHP server

var OUT = new Array (0x80,0x00,0x40,0x0026,0x0011,0x0014,0x0013,0x0018,0x0017,0x03FD,0x0116);
$.ajax({
    url: 'http://www.example.com/receiver.php'  //change example.com to your server
    ,type: 'POST' //use POST so don't have to worry about URL length
    ,data: {out: OUT} //pass contents of 'OUT' in variable 'out'
    ,dataType: 'json' //use JSON formatting of data
    ,error: function() { 
        alert("Failed to contact server"); 
    }
    ,complete: function() {
        alert("Finished sending data to server.");
    }
});

In receiver.php

$OUT = json_decode( $_POST['out'] ); // 'out' matches the parameter name in jQuery Ajax call
print_r( $OUT ); //print contents of array $OUT

JS array to PHP

3 Answers3