I have a problem I'd like to solve to not have to spend a lot of manual work to analyze as an alternative.
I have 2 JSON objects (returned from different web service API or HTTP responses). There is intersecting data between the 2 JSON objects, and they share similar JSON structure, but not identical. One JSON (the smaller one) is like a subset of the bigger JSON object.
I want to find all the interesecting data between the two objects. Actually, I'm more interested in the shared parameters/properties within the object, not really the actual values of the parameters/properties of each object. Because I want to eventually use data from one JSON output to construct the other JSON as input to an API call. Unfortunately, I don't have the documentation that defines the JSON for each API. :(
What makes this tougher is the JSON objects are huge. One spans a page if you print it out via Windows Notepad. The other spans 37 pages. The APIs return the JSON output compressed as a single line. Normal text compare doesn't do much, I'd have to reformat manually or w/ script to break up object w/ newlines, etc. for a text compare to work well. Tried with Beyond Compare tool.
I could do manual search/grep but that's a pain to cycle through all the parameters inside the smaller JSON. Could write code to do it but I'd also have to spend time to do that, and test if the code works also. Or maybe there's some ready made code already for that...
Or can look for JSON diff type tools. Searched for some. Came across these:
https://github.com/samsonjs/json-diff or https://tlrobinson.net/projects/javascript-fun/jsondiff
https://github.com/andreyvit/json-diff
both failed to do what I wanted. Presumably the JSON is either too complex or too large to process.
Any thoughts on best solution? Or might the best solution for now be manual analysis w/ grep for each parameter/property?
In terms of a code solution, any language will do. I just need a parser or diff tool that will do what I want.
Sorry, can't share the JSON data structure with you either, it may be considered confidential.