Junit protected method

Question

I'm wondering about a nice way to deal with a protected method in Junit.

Assuming I want to test a class called A which has a protected member and constructor. I understood that in order to test the class A I should write another class called ATest which might extend TestCase ( this should be mandatory in Junit3 ). Because I want to test a protected method and because A has a protected constructor, my test class ATest should also extend the class A where that method is implemented in order to be able to create that class and to access to the method.

could be a double inheritance from both classes a nice solution?

P.S I've already Known that in Junit 4 the inheritance from the TestCase might be avoided.

Can you explain why you would,like to extend TestCase? I think you should be able to do what you are saying and extend A to publicize its protected methods. I've dine it with NUnit and it works just fine — cowboydan, Oct 12 '12 at 00:10
possible duplicate of [junit & java : testing non-public methods](http://stackoverflow.com/questions/440786/junit-java-testing-non-public-methods) — Ciro Santilli OurBigBook.com, Feb 11 '15 at 13:55

score 17 · Accepted Answer · answered Oct 12 '12 at 00:12

17

To gain access to A's protected members, you can just put A and ATest in the same package.

answered Oct 12 '12 at 00:12

matt b

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+1 - this is a common convention for testing both protected and package private (default) methods. – Jeanne Boyarsky Oct 13 '12 at 13:01

score 1 · Answer 2 · answered Oct 12 '12 at 00:00

1

Java doesn't allow multiple inheritance of implementation. You can implement multiple interfaces.

I would prefer using reflection to get at methods for testing that I don't want clients to know about. Works for private methods, too.

answered Oct 12 '12 at 00:00

duffymo

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Junit protected method

2 Answers2