Modify parseInt method: Javascript

Question

I do not want use each and every time parseInt('08', 10) for each string to integer conversion,

Can we modify parseInt method, so that i can use only parseInt('08') instead of parseInt('08', 10).?

Answer 1

Instead of modifying the built-in function parseInt, you can define your own function like this:

function prseInt(n)
{
    return parseInt(n, 10);
}

And replace all the occurences of parseInt(n, 10) you have used in your app with prseInt(n).

Fine, if you still wanna redefine, you can do this:

var origParseInt = parseInt;
parseInt = function(n) {
     return origParseInt(n, 10);
}

And it works!

Fiddle: http://jsfiddle.net/QKKwv/

Answer 2

Use simply a + operator in front of your string, to perform a type coercion (and no need to call parseInt())

var str = "08";
var num = +str;

console.log(num, typeof num);  // 8, number

Answer 3

parseInt(xx) (ie, without the radix parameter) will work perfectly fine 99% of the time, what it will do is attempt to guess what base you are after.

For a single number like 8 it will correctly guess basse10 and give you integer 8. The problem is a string like 08 it will guess what you want is octal, and converting "08" to octal returns zero.

You should ALWAYS be providing the radix parameter whenever using parseInt.