Using cin.eof()

Question

I have some code and I wanted to use cin.eof() to stop my program from reading the input. I was thinking of doing:

char array[10]
while(!cin.eof())
{
  for(int i = 0; i < 10; i++)
  {
    cin >> array[i];
  }
}

And the code goes on. However, when I click '\n', my output is outputted. When i click cntrl + d, (on a UNIX terminal) the program performs the output again and then proceeds to end. How do I get it so that my program stops reading at a newline and prints my output when I type cntrl + d only once?

Thanks.

*"I wanted to use cin.eof() to stop my program from reading the input"* - [No, you don't](http://stackoverflow.com/q/5605125/743214). — Christian Rau, Oct 15 '12 at 08:36

score 1 · Answer 1 · answered Oct 15 '12 at 08:11

1

First, cin.eof() doesn't do anything useful until input has failed. You never want to use it at the top of a loop.

Secondly, it's not really clear to me what you are trying to do. Something like:

std::string line;
while ( std::getline( std::cin, line ) ) {
    //  ...
}

perhaps? This will read a line of text into the variable line, until end of file; when you encounter an end of file, the input will fail, and you will leave the loop.

answered Oct 15 '12 at 08:11

James Kanze

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What if I cant use strings? I've already constructed my program with char arrays – user1567909 Oct 15 '12 at 08:30
@user1567909 Then you'll have to use the member `istream::getline`, specifying a length, and looping or taking other action if the length is exceeded. In general, not using `string` for this sort of thing is a guaranteed way of making the code unnecessarily complex and fragile. – James Kanze Oct 15 '12 at 11:31

Using cin.eof()

1 Answers1

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