How can I POST parameters with a file object to a URL using httplib in python web services.
Am using the following scripts:
import httplib
import urllib
params = urllib.urlencode({"@str1":"string1", "@str2":"string2", "@file":"/local/path/to/file/in/client/machine", "@action":"action.php" })
headers = {"Content-type":"application/pdf , text/*" }
conn = httplib.HTTPConnection("192.168.2.17")
conn.request("POST", "/SomeName/action.php", params, headers)
response = conn.getresponse()
print response.status, response.reason
data = response.read()
data
conn.close()
And I have the following output:
200
OK
<html>.....some html code </html>
I wrote some php code for save those string and the file in DB My problem is that, Am only getting the file path as a sting but not my file. May be I have to send the file object like,
file_obj = open("filename.txt","r")
conn.request("POST", "/SomeName/action.php", file_obj, headers)
But I want to send both strings and file. Any suggestions to solve this?
EDIT I change my code as follows: When i send a pdf file, by directly using httplib, to my server the file saves as BIN file.
def document_management_service(self,str_loc_file_path,*args):
locfile = open(str_loc_file_path,'rb').read()
host = "some.hostname.com"
selector = "/api/?task=create"
fields = [('docName','INVOICE'),('docNumber','DOC/3'),('cusName','name'),('cusNumber','C124'),('category','INVOICE'),('data','TIJO MRS,SOME/DATA/CONTENT,Blahblah,2584.00,blahblah'),('action','create')]
files = [('strfile','File.pdf',locfile)]
response = self.post_multipart(host, selector, fields, files)
print response
pass
def post_multipart(self,host, selector, fields, files):
content_type, body = self.encode_multipart_formdata(fields, files)
h = httplib.HTTP(host)
h.set_debuglevel(1)
h.putrequest('POST', selector)
h.putheader('content-type', content_type)
h.putheader('content-length', str(len(body)))
h.putheader('Host', host)
h.endheaders()
h.send(body)
errcode, errmsg, headers= h.getreply()
return h.file.read()
def encode_multipart_formdata(self, fields, files):
LIMIT = '----------lImIt_of_THE_fIle_eW_$'
CRLF = '\r\n'
L = []
for (key, value) in fields:
L.append('--' + LIMIT)
L.append('Content-Disposition: form-data; name="%s"' % key)
L.append('')
L.append(value)
for (key, filename, value) in files:
L.append('--' + LIMIT)
L.append('Content-Disposition: form-data; name="%s"; filename="%s"' % (key, filename))
L.append('Content-Type: %s' % self.get_content_type(filename))
L.append('')
L.append(value)
L.append('--' + LIMIT + '--')
L.append('')
body = CRLF.join(L)
content_type = 'multipart/form-data; boundary=%s' % LIMIT
return content_type, body
def get_content_type(self, filename):
return mimetypes.guess_type(filename)[0] or 'application/octet-stream'
I have debug the request which shows as:
[('content-length', '4191'), ('accept-ranges', 'bytes'), ('server', 'Apache/2.2.12 (Ubuntu)'), ('last-modified', 'Tue, 23 Oct 2012 04:46:36 GMT'), ('etag', 'W/"567dd-105f-4ccb2a7a9a500"'), ('date', 'Tue, 23 Oct 2012 04:46:36 GMT'), ('content-type', 'application/pdf')]
multipart/form-data; boundary=----------lImIt_of_THE_fIle_eW_$
And I didn't try requests,Coz I would like to solve this with httplib(without any external lib)