PHP regular expression match first occurrences?

Question

http://someurlhere.com|http://sometexturl.com|sometexthere

i want to extract only the first url which is before the | , http://someurlhere.com

i have written regular expression

\bhttp(.*)\|\b

but its capture all the occurences of |

Thanx help is appreciated

Not really an answer to your question; but consider using `explode()` (http://php.net/manual/en/function.explode.php) — user254875486, Oct 18 '12 at 11:48
I don't understand what you're trying to achieve. You're trying to get the first part of text that is an URL (eg. prefixed with http://)? Does the http:// have to be part of the resulting match? Because as of now, your match would be `://someurlhere.com`. — bummzack, Oct 18 '12 at 12:02

Toto · Answer 1 · 2012-10-18T12:02:28.857

9

Make the .* ungreedy : .*?

\bhttp(.*?)\|\b

If you want to match only after the first | do:

\|http://(.*?)\|

with this, the url is in $1

edited Oct 18 '12 at 12:02

answered Oct 18 '12 at 11:47

Toto

sorry i tried this one ,its works but for this kind http://someurlhere.com|http://sometexturl.com|sometexthere not working – Fawad Oct 18 '12 at 11:53
@Fawad: What do you obtain with your example? – Toto Oct 18 '12 at 11:58
Thanx got it , i was using global regular expression , thanx again . can u do me one more help . how can i extract only url becuase of this pattern | is also coming in match :) – Fawad Oct 18 '12 at 12:01
i have edited the main question can u please read again thanx – Fawad Oct 18 '12 at 12:12
@Fawad: with my second regex, the url is in the first capture group `$1` – Toto Oct 18 '12 at 12:33

score 1 · Answer 2 · edited May 23 '17 at 12:18

1

This isn't a exact answer, but I will point you towards information that help you solve this issue!

edited May 23 '17 at 12:18

Community

answered Oct 18 '12 at 11:48

Hultin

score 1 · Accepted Answer · answered Oct 18 '12 at 11:50

1

No need for regex. I see you tagged it PHP.

$boom = explode('|', 'http://someurlhere.com|sometexturl.com|sometexthere');
$url = $boom[0];
echo $url;

Output:

http://someurlhere.com

answered Oct 18 '12 at 11:50

ohaal

3 Answers3