Displaying once repeat elements on array with jquery or php

Question

How to display once elements of array ?. For example

var array = ["b","c","c","a","d","e","a","d"]

show => ["a","b","c","d","e"] ?

Any example ?

Have a look to [array_unique](http://php.net/manual/en/function.array-unique.php) for a PHP function. — Alain Tiemblo, Oct 22 '12 at 04:57
possible duplicate of [Javascript array sort and unique](http://stackoverflow.com/questions/4833651/javascript-array-sort-and-unique) — Burhan Khalid, Oct 22 '12 at 06:54

doublesharp · Accepted Answer · 2012-10-22T05:06:43.880

Use the array_unique() function to remove the duplicates and sort - http://php.net/manual/en/function.array-unique.php

Following up with the array_values() function will remove the gaps in the array index - http://php.net/manual/en/function.array-values.php

// initialize array
var $array = array("b","c","c","a","d","e","a","d");
// remove duplicates and sort by string value
$array = array_unique($array, SORT_STRING);
// reindex array (numeric index will have gaps where the duplicates where removed)
$array = array_values($array);
// show results
print_r($array);

In Javascript/jQuery you can use the unique() and sort() methods

// initialize array
var array = ["b","c","c","a","d","e","a","d"];
// remove duplicate values
array.unique();
// sort remaining items
array.sort();

If you are sorting numbers in Javascript, you would need to pass a function, as the array is sorted lexicographically be default

array.sort(function(a,b){return a - b;});

score 1 · Answer 2 · answered Oct 22 '12 at 05:00

1

PHP

array_unique($array, SORT_STRING)

jQuery

array.unique()

answered Oct 22 '12 at 05:00

Mihai Matei

24,166
5
32
50

score 0 · Answer 3 · answered Oct 22 '12 at 05:00

0

in php you should use array_unique and sort for sorting array

$arr = array("b","c","c","a","d","e","a","d");
sort($arr);
print_r(array_unique($arr));

answered Oct 22 '12 at 05:00

Pragnesh Chauhan

8,363
9
42
53

score 0 · Answer 4 · edited May 23 '17 at 11:56

0

var names = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
var uniqueNames = [];
$.each(names, function(i, el){
    if($.inArray(el, uniqueNames) === -1) uniqueNames.push(el);
});

source:stack overflow

edited May 23 '17 at 11:56

Community

1
1

answered Oct 22 '12 at 05:02

Arun Killu

13,581
5
34
61

A much easier solution would be to use `names.unique()` – doublesharp Oct 22 '12 at 05:14
yes ,i posted bcoz he asked for solution either in php or js – Arun Killu Oct 22 '12 at 05:25
`unique()` is a Javascript function, PHP has a similar function `array_unique()`. Javascript syntax is `array.unique()` and PHP is `array_unique($array)`. – doublesharp Oct 22 '12 at 05:28

score 0 · Answer 5 · answered Oct 22 '12 at 07:14

qustion asked:- How to display once elements of array ?. For example

var array = ["b","c","c","a","d","e","a","d"]

show => ["a","b","c","d","e"] ?

Any example ?

answer:- $arr = array("b","c","a","d","e","a","d");

$unique = array_unique($arr);//remove all duplicate values

sort($unique);//sort is done here

echo ""; print_r($unique );//shows show => ["a","b","c","d","e"]

Displaying once repeat elements on array with jquery or php

5 Answers5